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laila [671]
3 years ago
9

What is common to all elements in the same group on the periodic table

Chemistry
2 answers:
marin [14]3 years ago
3 0
They all have the same number of electrons.
Hoochie [10]3 years ago
3 0
They all possess the same number of outermost or valence electrons in their outermost electron shell.
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Cation a has a +3 charge and is small. cation b has a +1 charge and is large. which is more likely to occupy negatively charged
oksian1 [2.3K]

Correct Answer: Cation -A

Given that both the cations, cation-A and cation -B have the same concentrations.

Charge on cation-A is +3, while charge on cation- B is +1. Cations with higher charge can easily substitute those present on the clay minerals. Cations with higher charge have a greater affinity for the negatively charged sites present on the clay mineral. So, cation -A with a charge of +3 is more likely to occupy the anionic sites on the clay mineral.

6 0
3 years ago
What is the velocity of a wave with a wavelength of 0.03 m and a frequency of
Anastasy [175]

Answer:

A

Explanation:

Got a calculation of 8.05297

6 0
3 years ago
Read 2 more answers
Which group period does neon belong to??
Liula [17]
Neon belongs to 2nd Period & 18th Group
8 0
3 years ago
Explain Garri industry<br>​
olasank [31]

Answer:

In West Africa, garri refers to the creamy granular flour obtained by processing the starchy tuberous roots of freshly harvested cassava. ... Flour foodstuffs mixed with cold or boiled water are a major part of the diet amongst the various ethnicities of Nigeria, Benin Republic, Togo, Ghana, Guinea, Cameroon and Liberia.

Explanation:

4 0
4 years ago
In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion
love history [14]
The balanced reaction would be:<span>

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

</span>11.16 mol O2<span> (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =</span>11.16 mol CO2<span> x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L</span>
7 0
4 years ago
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