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3 years ago

Evaluate the following expression when x = -4 and y = 4.

Mathematics

2 answers:

frozen [14]3 years ago

8 0

Answer:

250/3

Step-by-step explanation:

Putting the values of x and y

(-4)^6-(-4)/4(4)

4096+4/16

4100/6

250/3

AleksandrR [38]3 years ago

3 0

Answer:

-509.375

Step-by-step explanation:

-4 to the sixth power is -4069 and that plus -4 equals -4075. -4075 divided by 8 equals -509.375 so that is your answer.

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If a person is randomly selected, find the probability that his or her birthday is not in may.

Lerok [7]

Supposing 30 days in the month of May (which is not always same in every year),we have,
S= Sample Space
n(S)=total days in a year=365 days
n(E)=no of favourable events
= no of days in the month of May=30 days
Then the probability is of favourable events is,
P(E)=n(E)/n(S)=30/365=6/73
Now,the probability that the birthday is not in May is,
P'(E) =1-6/73=67/73 ANS!!!

5 0

3 years ago

Find the distance between points A and F

lesya [120]

Answer: $2\frac{1}{4}$

This is the mixed number 2 & 1/4

whole part = 2

fractional part = 1/4

=======================================================

Explanation:

Each tickmark represents $\frac{1}{4}$

If you count the spaces between points F and A, you should count out exactly 9 spaces as shown in the diagram below.

We'll multiply that value 9 by $\frac{1}{4}$ to get our final answer.

$9*\frac{1}{4} = \frac{9}{4}$

$\frac{9}{4} = \frac{8+1}{4}\\\\\frac{9}{4} = \frac{8}{4}+\frac{1}{4}\\\\\frac{9}{4} = 2+\frac{1}{4}\\\\\frac{9}{4} = 2 \frac{1}{4}\\\\$

The result we get is a mixed number 2 & 1/4, meaning the whole part is 2 and the fractional part is $\frac{1}{4}$

7 0

3 years ago

Read 2 more answers

63% of US adults opposed to taxes on junk food and soda. You randomly select 10 US adults. Find the probability that the number

WARRIOR [948]

Answer:

a) 0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

b) 0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

c) 0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they are opposed to taxes on junk food and soda, or they are not. Each adult is independent of other adults, which means that the binomial probability distribution is used to solve the question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

63% of US adults opposed to taxes on junk food and soda.

This means that $p = 0.63$

You randomly select 10 US adults.

This means that $n = 10$

(a) exactly one

This is $P(X = 1)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008$

0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

(b) at least four

This is

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.63)^{0}.(0.37)^{10} \approx 0$

$P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008$

$P(X = 2) = C_{10,2}.(0.63)^{2}.(0.37)^{8} = 0.0063$

$P(X = 3) = C_{10,3}.(0.63)^{3}.(0.37)^{7} = 0.0285$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0008 + 0.0063 + 0.0285 = 0.0356$

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0356 = 0.9644$

0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

(c) less than eight

This is

$P(X < 8) = 1 - P(X \geq 8)$

In which

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.63)^{8}.(0.37)^{2} = 0.1529$

$P(X = 9) = C_{10,1}.(0.63)^{9}.(0.37)^{1} = 0.0578$

$P(X = 10) = C_{10,2}.(0.63)^{10}.(0.37)^{0} = 0.0098$

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1529 + 0.0578 + 0.0098 = 0.2205$

$P(X < 8) = 1 - P(X \geq 8) = 1 - 0.2205 = 0.7795$

0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

5 0

3 years ago

Does this graph show a function? Explain how you know.

Andrew [12]

Answer: C

Because it fails the vertical line test.

Put a pencil vertical on the graph.

Drag it along, if there are 2 lines that touch the pencil, it fails the test.

If there's only one, it passes.

5 0

3 years ago

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Three multiplied by a number g

Leviafan [203]

Thats gonna be 3g...

3 0

3 years ago

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