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3 years ago

What is the remainder when 6x+12 is divided by 2x-8.

Mathematics

2 answers:

bagirrra123 [75]3 years ago

7 0

Answer:

4(3x-2)

Step-by-step explanation

6x+12/2x-8

6x+6x-8

12x-8

4(3x-2)

sasho [114]3 years ago

4 0

Answer:

Step-by-step explanation:

2x-8 ) 6x+12 ( 3

6x-24

- +

-----------

quotient=3

remainder=36

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3 years ago

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3 years ago

If the triangles are congruent, then X=?

steposvetlana [31]

Answer:

Hi there!

The correct answer to this question is: x=3

Step-by-step explanation:

because these two triangles are similar, that means the hypotenuse are similar. which means you can set the sides equal to each other like this:

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3 years ago

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3 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

3 years ago

What is the remainder when 6x+12 is divided by 2x-8.​

What is the remainder when 6x+12 is divided by 2x-8.