Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
Well, in order to answer this problem we need to use the <span>the Pythagorean Theorem and the it will be like this:
cos = x / hypotenuse
cos= 12/13
I think with this you can figure the rest out. Hope this helps</span>
I did this two years ago. Hope I can help you.
It will take him 80 minutes, or an hour and 20 minutes
