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Gala2k [10]
3 years ago
15

How many square yards of paper would be needed to wrap this cube

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

Area of the paper required to wrap the cube = 600 yards^2

Step-by-step explanation:

The given figure is in the shape of a Cube that has all its sides equal with a Side(a)= 10 yards

The paper required to wrap the cube= Area of the cube

Area of Cube :

                         6*a*a\\\\=6*10*10\\\\=600 yards^2\\\\

The area of the paper required to wrap the cube is  600 yards^2

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Số hạng đầu và số hạng thứ 2 của một cấp số nhân lần lượt là x+2 và x^2 -4 số hạng thứ 3 của cấp số nhân này là
GenaCL600 [577]

Answer:

x³-2x²-4x+8

Step-by-step explanation:

a1=x+2

a2=x²-4⇒q=a2/a1=x-2

⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8

3 0
3 years ago
Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.
rodikova [14]

Answer:

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x)^2 = x^2

121 + 121^2 - 121(2)x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not

7 0
3 years ago
I just need 30 please
PIT_PIT [208]

In the smaller triangle, let y be the length of the smallest leg. Then the smallest leg in the larger triangle is 14-y.

Within the scope of the smaller triangle, we have y such that

x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}

Then within the larger the triangle, we would have

x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2

Now we can solve for x:

x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2

\implies x=12

8 0
3 years ago
How to find the value of x in an exponential function?
aleksklad [387]
YOU CAN DO Y=MX+B AND YOU WILL FIND YOUR ANSWER
6 0
3 years ago
The area of a triangle is 36 sq. inches. If the base of the triangle is 6 inches, what is its height?
tresset_1 [31]
According to your question the height for the triangle is 12inch
3 0
4 years ago
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