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Sophie [7]
4 years ago
13

50 points decreased by 26% is how many points?

Mathematics
1 answer:
vampirchik [111]4 years ago
6 0
The first one is 13 points and the 2nd one is 8. I'm pretty sure, hope this helps! :)
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A flagpole is supported by a wire fastened 60 feet from its base. The wire is longer than the height it reaches on the flagpole.
maxonik [38]

Answer:

135.5ft

Step-by-step explanation:

THIS COMPLETE THE QUESTION

flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.

Let X be the length of the wire

Let y be the height of the pole

X= Y + 14

Y= X -14

We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)

Using Pythagoras theorem

X²= 60² + Y²

X² = 3600 + Y²

if we subsitute for Y we have

X² = 3600 + (X -14)²

X² = 3600 +X² -14X-14X+196

X²-X²+ 28X= 3600+196

28X= 3796

X= 3796/28

=135.5ft

hence length of the wire is 135.5ft

8 0
3 years ago
The circle below is centered at (4, -1) and has a radius of 3. What is its
denis23 [38]

Answer:

Answers C and D are proably missing the y term.  I'll assume they are:

C. (x-4)² + (y-1)² = 9

D. (x-4)² + (y-1)² = 3

A, is the equation that produces the drawn circle.

Step-by-step explanation:

See the attached image for explanation.

6 0
2 years ago
A school had 620 students win academic success awards in 2014. In 2015, the school had 527 students win academic success awards.
wolverine [178]

Answer:

B

Step-by-step explanation:

(527÷620)×100%

0.85×100%

85%

5 0
3 years ago
Find the range of the data set: 28, 11, 25, 4, 24
Delicious77 [7]
The range is the largest number subtracted by the smallest number.
28-4=24 is the range.
3 0
3 years ago
Read 2 more answers
At the beginning of year 1, Jonah invests $300 at an annual
olga55 [171]

At the beginning of year 6, that means 5 years only have elapsed, thus t = 5.

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$300\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5

6 0
4 years ago
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