I can tell you that you have to multiply Alonzo score by 16
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Answer:
angle B: 39
AC: 7.288
AB: 11.58
(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)
Step-by-step explanation:
To solve this we will use SOH, CAH, TOA
we have the angle and the one opposite to it which means we can use either SOH or TOA
let's use TOA
tan(51)=(9/x)
x= 7.288
We can now use pahtagaryous theroem to solve for the hyptonouse
we have
9²+7.288²=C²
C=11.58
Finally, to find angle B we will recall that the angles of a triangle must add to 180.
51+90+a=180
a=39
Answer:
4:9
Step-by-step explanation:
Area is squaring and Volume is cubing
So it'd be 2^2:3^3, or 4:9
I hope this helped and have a good rest of your day!
Answer:
(19-12):12*100 =
(19:12-1)*100 =
158.33333333333-100 = <u>58.33</u>
Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
