Answer:
72.69% probability that between 4 and 6 (including endpoints) have a laptop.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
A study indicates that 62% of students have have a laptop.
This means that 
You randomly sample 8 students.
This means that 
Find the probability that between 4 and 6 (including endpoints) have a laptop.






72.69% probability that between 4 and 6 (including endpoints) have a laptop.
A(t) = P(1+(r/n))^(nt)
A(5) = 1000(1+0.12/2)^(2*5)
A(5) = 1000(1.06)^(10)
A(5) = $1790.85
Answer: 13 sheets of paper
Step-by-step explanation:
We are given the dimensions of the box and the wrap paper:
Box:

Warp paper:

Now we need to find the surface area of the box and the area of the wrap paper:
Box:




Warp paper:

Dividing the area of the box by the area of the paper:

This means Angel's dad needs to purchase 13 sheets of wrapping paper.
Here's one way to do it.
AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence
Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
Perimeter = 2*(length +width)
perimeter = 2*(3x + (3x +(2x+6)))
.. = 2*(3x +3x +2x +6)
.. = 2*(8x +6)
perimeter = 16x +12
If x=3, the perimeter is 16*3 +12 = 60 inches.