Ask question

Ask question

All categories

3 years ago

5

Some friends decide to go to the aquarium together. Each person pays $7.50 to get in. They spend a total of $40 for the shark ex

hibit. The total cost is $70. Solve 7.5x+40=70 to find how many people went to the aquarium.

1 answer:

murzikaleks [220]3 years ago

7 0

Answer:

4 people went to the aquarium

Step-by-step explanation:

You might be interested in

Given a dilation with the origin O (0, 0), by observation determine the scale factor "K."

BaLLatris [955]

When the dilation is about the origin, the scale factor multiplies every coordinate. That is (considering the x-coordinate) ...
6·k = 3
k = 3/6 = 1/2

The appropriate choice is
1. 1/2

4 0

3 years ago

Read 2 more answers

Sales at a book store increased from 5000 to 10000. This year sales dicreased to 5000 from 10000.

erastovalidia [21]

It's basically 5,000*2=10,000
and 10,000/2=5,000. your answer would be either they multiplied 5,000 by 2 and 10,000 divided by 2, they increased the sales by 5,000

6 0

3 years ago

Read 2 more answers

Consider the points A(–5, 3) and B(–2, 5).

MariettaO [177]

Answer:

New coordinates for A - (2, -5)

New coordinates for B - (5, -3)

Step-by-step explanation:

When translating a point to the 7 units right, you must add 7 to the x coordinate. When translating a point 8 units down you must subtract 8 from the y coordinate.

4 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

Drag steps of the solution into order to solve for x in the equation 6(x-5) = 54

telo118 [61]

The steps of the solution into order to solve for x in the equation 6(x-5) = 54 are:

A. 6x – 30 = 54
B. 6x = 84
D. x = 14

Given the expression 6(x-5) = 54

Expand the expression in parenthesis using the distributive law;

6x - 6(5) = 54

6x - 30 = 54

Add 30 to both sides

6x - 30 + 30 = 54 + 30

6x = 84

Divide both sides by 6

6x/6 = 84/6

x = 14

Therefore the steps of the solution into order to solve for x in the equation 6(x-5) = 54 are:

A. 6x – 30 = 54
B. 6x = 84
D. x = 14

Learn more on equations here; brainly.com/question/2972832

7 0

2 years ago