2 years ago

PLEASE HELP WITH ALGEBRA WILL GIVE BRAINLIEST

Mathematics

1 answer:

Allushta [10]2 years ago

3 0

Answer:

$\frac{ad}{bd} + \frac{cb}{bd}$

Step-by-step explanation:

$\frac{a}{b} + \frac{c}{d}$

$\frac{ad}{bd} + \frac{cb}{bd}$ Multiply by the LCD (bd)

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While shopping for clothes, Daniel spent $34 less than 3 times what Jaclyn spent. Daniel spent $14. Write and solve an equation

topjm [15]

Answer: Jaclyn spent $48

Step-by-step explanation:

3x - 34 = 14

3x = 14+34

X = 48/3 = 16

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3 years ago

Solve x/2 + y/3 = 1 for x

denis23 [38]

Answer:

$x$ = - $\frac{2y}{3}$ + 2

Step-by-step explanation:

Solve for $x$ by simplifying both sides of the equation , isolating the variable.

Hope this helped you, Also please let me know if anything is unclear or wrong!

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3 years ago

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What is 40 x 40? Solve that!

jolli1 [7]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

1. W+ 4 = 16

ExtremeBDS [4]

1. W=16-4=12
2. X=-12-7=-19
3. W=6+15=21
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8 0

3 years ago

Need help with this....

Yakvenalex [24]

Answer:

$\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}$

Step-by-step explanation:

$f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}$

$=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2$

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3 years ago