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IrinaK [193]
3 years ago
13

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
Katena32 [7]3 years ago
4 0

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

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1. (7 , 0) and (11 , 3) → B and D

substitute each coordinate point into the left side of the equation and if equal to 21 then it is a solution.

( 7 , 0) → (3 × 7) - ( 4× 0)  = 21 - 0 = 21  

(11 , 3) → (3 × 11 )  - ( 4 × 3) = 33 - 12 = 21

2. ( 2 , - 9 ) is a solution to the equation

substitute the coordinates into the equation and if equal to 13 the it is the solution.

(2 , - 9 ) → (5 × 2 ) - (-9)/3 = 10 + 9/3 = 10 + 3 = 13

(3 , - 6) → (5 × 3) - (- 6)/3 = 15 + 6/3 = 15 + 2 = 17

thus (2 , -9 ) is the solution

4. x- intercept = (- 45 , 0)

to find the x- intercept let y = 0

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3 years ago
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