All categories

3 years ago

Vertex of y=5x^2-10x+1

Mathematics

1 answer:

kirill [66]3 years ago

4 0

Convert to vertex form:-

y = 5(x^2 - 2x) + 1

y = 5[(x - 1)^2 - 1] + 1

y = 5(x - 1)^2 - 4

vertex is (1, -4)

You might be interested in

You previously found the mean of this data set. Use that in answering the question. 63, 89, 92, 73, 79, 72, 34, 36, 94, 21, 25,

kicyunya [14]

Answer:

Sum of squares of differences = 11239.74

Step-by-step explanation:

We are given the following data set:

63, 89, 92, 73, 79, 72, 34, 36, 94, 21, 25, 93, 22, 90, 79

We have to calculate the sum of square of the data set.

Formula:

$\text{Sum of square of differences} = \sum (x_i -\bar{x})^2$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{962}{15} = 64.13$

Sum of squares of differences =

1.284444444 + 618.3511113 + 776.5511113 + 78.61777778 + 221.0177779 + 61.88444445 + 908.0177776 + 791.4844443 + 892.017778 + 1860.484444 + 1531.417778 + 833.2844446 + 1775.217777 + 669.0844446 + 221.0177779

= 11239.74

3 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Please help ❗️❗️❗️❗️ Please! I will reward brainly

zhuklara [117]

Hey there :)

We know the distance formula is:
D = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓   ↓
x₁ y₁ x₂ y₂
We plug in the values
D = $\sqrt{(8 -(-10))^2+(5-(-5))^2}$
  ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = $\sqrt{(-2-10)^2+(1-0)^2}$
≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = $\sqrt{((7-4)^2+(-8-8)^2}$
≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = $\sqrt{(8-(-10))^2+(8-(-4))^2}$
  ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = $\sqrt{(-8-6)^2 + (9-(-3))^2}$
≈ 18.4 (nearest tenth)

You can find the matching below :)

8 0

3 years ago

Add.<br> -6.3+(-9.7)<br> - 6.3+(-9.7) =<br><br> (Type an integer or a decimal.)

vlada-n [284]

7.6992 buds no sis
BDIS yes yes teye what they said

3 0

2 years ago

If you divide 3/4 by 4/7 what is the answer in fraction form?

victus00 [196]

The answer is 21/16

8 0

3 years ago