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3 years ago

Can you please help me on -5(x+2)=-(-5x+1)-x

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

x = -1

Step-by-step explanation:

Step 1: Distribute

-5(x + 2) = -(-5x + 1) - x

-5x - 10 = 5x - 1 - x

-5x - 10 = 4x - 1

Step 2: Solve for x

-5x - 10 + 5x = 4x - 1 + 5x

-10 + 1 = 9x - 1 + 1

-9 / 9 = 9x / 9

-1 = x

Answer: x = -1

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Answer:

Rate of change = 150%

Rate of change = 100%

Step-by-step explanation:

Find:

Rate of change

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Rate of change = 150%

Rate of change = [(6-3)/3]100

Rate of change = 100%

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3 years ago

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I = prt
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3 years ago

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3 years ago

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What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

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4 years ago

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A scientist writes the equation n(h)100e^0.25h to model the growth of a certain bacteria in a petri dish, where N represents the

Natasha2012 [34]

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

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