All categories

3 years ago

What does this equal -7g = -98

Mathematics

2 answers:

malfutka [58]3 years ago

5 0

Divide both sides of the equation by -7.

$\frac{-7g}{-7} =\frac{-98}{-7}$

g = 14

tigry1 [53]3 years ago

5 0

-7g=-98 or more simply put divide -98 by -7 which gives you positive 14 with no remainder so g=14. :)

hope this helps

You might be interested in

3.5 m

marysya [2.9K]

Answer:

This question seems to be incomplete, I guess that we have a circular pool, with a diameter of 3.5 m.

Now, the circunference of a circle can be written as:

C = 2*pi*r

where:

pi = 3.14

r = radius = half of the diameter = 3.5m/2 = 1.75m

Then replacing those values in the equation for the circumference we have:

C = 2*3.14*1.75m = 10.99 m.

And knowing that the value of pi is actually larger than 3.14 (pi = 3.1415926535....)

We can safely round up the circumference to the next whole number, C = 11m

4 0

3 years ago

The table represents the function f(x)=2x+1

elena-14-01-66 [18.8K]

Maybe try using Photomath it works for me. Good luck

4 0

3 years ago

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$