How many electrons are required to balance the following half-reaction?
1 answer:
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<u>Answer:</u> The mass of water produced in the reaction is 47.25 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of ammonia = 29.7 g
Molar mass of ammonia = 17 g/mol
Putting values in equation 1, we get:
The given chemical reaction follows:
By stoichiometry of the reaction:
4 moles of ammonia produces 6 moles of water.
So, 1.75 moles of ammonia will produce = of water.
Now, calculating the mass of water by using equation 1, we get:
Molar mass of water = 18 g/mol
Moles of water = 2.625 moles
Putting values in equation 1, we get:
Hence, the mass of water produced in the reaction is 47.25 grams.