3. Pretend you're a farmer and you want to grow more crops. You have three different

Explain the regiochemical outcome for chlorination of bromobenzene.

Wittaler [7]

Answer:

See explanation

Explanation:

In a chemical reaction, a particular reaction path may be favoured due to the fact that it is energetically more favourable(lower energy sigma complex is formed).

The more the resonance structures produced in a particular reaction pathway, the more energetically favourable it is.

In the chlorination of bromobenzene, ortho attack and para attack are preferred because each of these pathways involves a sigma complex with__4________resonance structures. Attack at the meta position involves formation of a sigma complex with only____3_______ resonance structures. The reaction will proceed more rapidly via the_____lower_______ energy sigma complex, so attack takes place at the ortho and para positions in preference to the meta position.

4 0

3 years ago

01:58:46

Luden [163]

Answer:

6

Explanation:

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3 0

3 years ago

Question 1(Multiple Choice Worth 4 points)

zubka84 [21]

<u>Answer </u>

Answer 1 : 28.9 g of CO is needed.

Answer 2 : Six moles of $H_{2}O$ over Nine moles of $O_{2}$

Answer 3 : Four over two fraction can be used for the mole ratio to determine the mass of Fe from a known mass of $Fe_{2}O_{3}$ .

Answer 4 : Mass of $O_{2}$ = (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Answer 5 : 8.4 moles of sodium cyanide (NaCN) would be needed.

<u>Solution </u>

Solution 1 : Given,

Given mass of $Fe_{2}O_{3}$ = 55 g

Molar mass of $Fe_{2}O_{3}$ = 159.69 g/mole

Molar mass of CO = 28.01 g/mole

Moles of $Fe_{2}O_{3}$ = $\frac{\text{ Given mass of } Fe_{2}O_{3}}{\text{ Molar mass of } Fe_{2}O_{3}}$ = $\frac{55 g}{159.69 g/mole}$ = 0.344 moles

Balanced chemical reaction is,

$Fe_{2}O_{3}(s)+3CO(g)\rightarrow 2Fe(s)+3CO_{2}(g)$

From the given reaction, we conclude that

1 mole of $Fe_{2}O_{3}$ gives → 3 moles of CO

0.344 moles of $Fe_{2}O_{3}$ gives → 3 × 0.344 moles of CO

= 1.032 moles

Mass of CO = Number of moles of CO × Molar mass of CO

= 1.032 × 28.01

= 28.90 g

Solution 2 : The balanced chemical reaction is,

$2C_{3}H_{6}+9O_{2}\rightarrow 6CO_{2}+6H_{2}O$

From the given reaction, we conclude that the Six moles of $H_{2}O$ over Nine moles of $O_{2}$ is the correct option.

Solution 3 : The balanced chemical reaction is,

$4Fe+3O_{2}\rightarrow 2Fe_{2}O_{3}$

From the given balanced reaction, we conclude that Four over two fraction can be used for the mole ratio to determine the mass of Fe from a known mass of $Fe_{2}O_{3}$ .

Solution 4 : Given,

Given mass of $Zn(ClO_{3})_{2}$ = 150 g

Molar mass of $Zn(ClO_{3})_{2}$ = 232.29 g/mole

Molar mass of $O_{2}$ = 31.998 g/mole

Moles of $Zn(ClO_{3})_{2}$ = $\frac{\text{ Given mass of }Zn(ClO_{3})_{2} }{\text{ Molar mass of } Zn(ClO_{3})_{2}}$ = $(\frac{150\times 1}{232.29})moles$

The balanced chemical equation is,

$Zn(ClO_{3})_{2}}\rightarrow ZnCl_{2}+3O_{2}$

From the given balanced equation, we conclude that

1 mole of $Zn(ClO_{3})_{2}$ gives → 3 moles of $O_{2}$

$(\frac{150\times 1}{232.29})moles$ of $Zn(ClO_{3})_{2}$ gives → $[(\frac{150\times 1}{232.29})\times 3] moles$ of $O_{2}$

Mass of $O_{2}$ = Number of moles of $O_{2}$ × Molar mass of $O_{2}$ = $[(\frac{150\times 1}{232.29})\times 3] \times 31.998 grams$

Therefore, the mass of $O_{2}$ = (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Solution 5 : Given,

Number of moles of $Na_{2}SO_{4}$ = 4.2 moles

Balanced chemical equation is,

$H_{2}SO_{4}+2NaCN\rightarrow 2HCN+Na_{2}SO_{4}$

From the given chemical reaction, we conclude that

1 mole of $Na_{2}SO_{4}$ obtained from 2 moles of NaCN

4.2 moles of $Na_{2}SO_{4}$ obtained → 2 × 4.2 moles of NaCN

Therefore,

The moles of NaCN needed = 2 × 4.2 = 8.4 moles

3 0

3 years ago

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For the reaction 4FeCl2(aq) + 3O2(g) → 2Fe2O3(s) + 4Cl2(g), what volume of a 0.945 M solution of FeCl2 is required to react comp

Mnenie [13.5K]

Answer:

0.01M

Explanation:

Given paramters:

Volume of FeCl₂ = ?

Concentration = 0.945M

Number of molecules of O₂ = 4.32 x 10²¹molecules

Solution:

The balanced reaction equation is given below:

4FeCl₂ + 3O₂ → 2Fe₂O₃ + 4Cl₂

Now, to solve the problem we use mole relationship between the compounds.

We work from the known to the unknown compounds. Here, the known is the oxygen gas because from the given parameters we can estimate the number of moles of the reacting gas.

number of moles of O₂ = $\frac{number of elementary of particles}{6.02 x 10^{23}}$

number of moles of O₂ = $\frac{4.32 x 10^{21}}{6.02 x 10^{23}}$

number of moles of O₂ = 0.007mole

now, from the reaction equation we find the number of moles of the FeCl₂:

3 mole of O₂ reacted with 4 moles of FeCl₂

0.007mole of O₂ reacted with $\frac{4 x 0.007}{3}$ = 0.0096mole O₂

Now to find the volume of FeCl₂ we use the expression below;

volume of FeCl₂ = $\frac{number of moles}{concentration}$

= $\frac{0.0096}{0.945}$

= 0.01L

7 0

3 years ago

A moss begins to grow on a rock in an area that was previously uninhabited by life. This is an example of what??

Stels [109]

Answer: Primary succession

Explanation: The primary succession takes place at the places where the fungi, lichen and pioneer species grow on the substrate other than soil.

The moss and other plants starts growing when there is a suitable condition for their growth.

The place like rock and volcanic ashes are not fertile as soil for the growth of plants so when there is a growth of moss on the rock for the first time known as Primary Succession.

8 0

3 years ago

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