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GenaCL600 [577]
2 years ago
5

A woman is found dead on a boat floating in the middle of a lake at 4:30am. There is blunt force trauma to her head but no other

discernable damage. She is approximately 30 pounds overweight. She is wearing thermal clothing and a winter jacket, gloves, and hat. Climatological data indicate it was a clear, cold, and windy night with no precipitation. Calculate the time of death based only on a body temperature of 15.6°C (60.8°F)? Now consider the other factors presented. How would each affect this estimation?
Chemistry
1 answer:
Olenka [21]2 years ago
5 0

Answer:

Dead bodies lose one degree Celsius per hour, which we could deduce that the person died 12 hours ago.

Explanation:

On the other hand, it is very important to take into account that this number of hours is very approximate, since not only does it vary greatly with the environment and the acclimatization of the environment in which the person dies, but also in this specific case, insulating clothing was presented , which made the loss of body heat much more difficult and could easily be more than 12 hours.

The minimum for this particular situation is 12 hours to 24 hours possible postmortem.

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How many atoms are in carbon 12
Nataliya [291]

Answer:

6.02x10^23 atoms

Explanation:

From the background knowledge of Avogadro's hypothesis, we understood that 1mole of any substance contains 6.02x10^23 atoms. This implies that 1mole of carbon also contains 6.02x10^23 atoms.

1mole of carbon = 12g.

Therefore, 12g of carbon contains 6.02x10^23 atoms

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Que tipo de mistura tem a agua mineral?
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Answer:

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2 years ago
Consider the reaction h2(g) + cl2(g) ⇀↽ 2 hcl(g), which is exothermic as written. what would be the effect on the equilibrium po
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How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

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