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postnew [5]
3 years ago
11

How many grams of carbon are there in 706 grams of acetic acid

Chemistry
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

How many grams Acetic Acid in 1 mol? The answer is 60.05196.

We assume you are converting between grams Acetic Acid and mole?

(人◕ω◕)

Explanation:

You can view more details on each measurement unit:

molecular weight of Acetic Acid or mol

The molecular formula for Acetic Acid is CH3COOH.

The SI base unit for amount of substance is the mole.

1 grams Acetic Acid is equal to 0.016652245821785 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams Acetic Acid and mole.

Examples

1 grams Acetic Acid to mol = 0.01665 mol

10 grams Acetic Acid to mol = 0.16652 mol

20 grams Acetic Acid to mol = 0.33304 mol

30 grams Acetic Acid to mol = 0.49957 mol

40 grams Acetic Acid to mol = 0.66609 mol

50 grams Acetic Acid to mol = 0.83261 mol

100 grams Acetic Acid to mol = 1.66522 mol

200 grams Acetic Acid to mol = 3.33045 mol

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yawa3891 [41]

Answer:

CaF2

Explanation:

Calcium fluoride is a solid formed by the chemical combination of Calcium (Ca) and Fluorine (F). Two molecules of fluorine (F2) and one molecule of Calcium (Ca) are needed to form the Calcium Fluoride molecule.

An ionic bond is formed between the Calcium and Fluorine atoms i.e. electrons are transferred from calcium atoms to fluorine atoms. The calcium ion is a cation with formula; Ca2+ while fluorine is an anion with formula; F-. Hence, it takes two molecules of Fluorine ion (F-) to form a relatively stable and neutral molecule with 1 molecule of Calcium ion (Ca2+).

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3 years ago
What type of element is most abundant: metals, nonmetals, or metalloids?
AnnyKZ [126]
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3 years ago
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Phoenix [80]
Because the formation of rust is a kind of chemistry reaction.
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A certain compound was found to have the molecular formula C5H12O2. To which of the following compound classes could the compoun
IgorC [24]

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Explanation :

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where,

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H = number of hydrogen

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Hope this helps!
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