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DanielleElmas [232]
3 years ago
13

There are 768 beds in a hospital, each floor has 64beds, how many floors are there

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

There are 12 floors in a hospital.

Step-by-step explanation:\

Each floor has 64 beds, but the hospital has totally 768 beds

So, \frac{768}{64} = 12 (floors)

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A bookstore marks up the price of a book by 25% of the cost from the publisher. Therefore, the
lesya692 [45]

Answer:

(A)

  • P(60) = 78.98
  • When the bookstore spends $60 on a textbook, the student pays $78.98

Step-by-step explanation:

Given:

P(x) = 1.053(x+0.25x)

P(60) = 1.053(60+0.25*60)

=1.053(60+15)

=1.053(75)

P(60)=$78.98

Since x is the cost from the publisher, when the bookstore spends $60 on a textbook, the student pays $78.98.

<u>The correct option is A.</u>

3 0
3 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
What is the value of 3/10 to the power of three
Zielflug [23.3K]
0.003? 3/(10^3). Wdym
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3 years ago
Kevin weighed his loaded truck at a weigh station. It weighed 14 tons 500 lbs 9 oz. His empty truck weighed 2 tons 600 lbs 12 oz
LenaWriter [7]
None of these are correct my calculations are 11 tons 2138 Ibs 28 oz
7 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil
Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 83, \sigma = 3

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 83}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0
3 years ago
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