Answer:
x = 3
Step-by-step explanation:
In a 30-60-90 triangle the side between 60 and 90 degree angle is a, the side between 30 and 90 degree angle is a√3, and the hypotenuse is 2*a.
Given that the side that is supposed to be a is currently √3, we know that the missing side x must be:
a√3 (We know that a, in this case, is √3, so substitute)
x = (√3) * (√3)
x = 3
Answer:
perpendicular I believe
Step-by-step explanation:
I'd plot the points and make a line using a ruler to check though.
Answer:
-1 and 1 are the zeros
Step-by-step explanation:
Graph it and youll see that the curve touches the x axis at (-1,0) and (1,0)
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Steps in constructing a circumscribed circle on a triangle using a just a compass and a straight edge.
1) construct a perpendicular bisector of one side of ΔRST.
2) construct another perpendicular bisector of another side of ΔRST
3) the point where the two bisectors intersect will be the center of the circle.
4) place the compass on the center point, adjust its length to ensure that any corner of the triangle will be reached and draw the circumscribed circle.
