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prohojiy [21]
3 years ago
13

In ΔMNO, o = 63 cm, n = 23 cm and ∠N=30°. Find all possible values of ∠O, to the nearest degree.

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

No triangle possible

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Given: ABCD trapezoid<br> BC=1.2m, AD=1.8m<br> AB=1.5m, CD=1.2m<br> AB∩CD=K<br> Find: BK and CK
stepladder [879]

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

AD\parallelBC

\angle KBC=\angle KAD              (Corresponding angles)

\angle KCB=\angle KDA             (Corresponding angles)

By AA rule of similarity

\triangle KBC\sim \triangle KAD

Corresponding sides of similar triangles are proportional.

\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}

\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{2}{3}

3x=2x+3

x=3

The length of BK is 3 m.

\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{y}{y+1.2}=\frac{2}{3}

3y=2y+2.4

y=2.4

The length of CK is 2.4 m.

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3 years ago
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Answer:

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Step-by-step explanation:

4x-9y+x+y

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=(4x+x)+(-9y+y)

=5x+-8y

=5x-8y

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12/31 = 0.38 minutes per page 

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Lelu [443]

Answer:

y - 5 =  \frac{7}{4} (x - 1) \\ 4y - 20 = 7x - 7 \\ 4y = 7x  + 13 \\  y =  \frac{7}{4} x +  \frac{13}{4}

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