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Morgarella [4.7K]
3 years ago
13

The partial pressure of carbon dioxide in the atmosphere is 0.239 torr. Calculate the partial pressure in mm Hg and cant Round e

ach of your answers to 3 alg X 5 ?
Chemistry
1 answer:
victus00 [196]3 years ago
6 0

Explanation:

It is known that 1 torr equals 1 mm Hg.

Therefore, 0.239 torr will be converted into mm Hg as follows.

                     1 torr = 1 mm Hg

So,          0.239 torr = 0.239 torr \times \frac{1 mm Hg}{1 torr}

                                 = 0.239 mm Hg

It means that 0.239 torr is equal to 0.239 mm Hg.

Therefore, we can conclude that partial pressure of given carbon dioxide in mm Hg is 0.239 mm Hg.

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Calcular el volumen que ocupa 66 gramos de CO medido a 27°C y 624 mm Hg Dato: Masas atómicas: C= 12 y O=16 . R=62,4 mmHg L/mol K
jonny [76]

Respuesta:

72 L

Explicación:

Paso 1: Calcular los moles de CO

La masa molar de CO es 28,01 g/mol.

66g \times \frac{1mol}{28,01g} =2,4mol

Paso 2: Convertir la temperatura a Kelvin

Siempre que trabajamos con gases ideales, debemos convertir las temperaturas a la escala Kelvin. Usaremos la siguiente formula.

K = °C + 273,15

K = 27°C + 273.15

K = 300 K

Paso 3: Calcular el volumen de gas

Usaremos la ecuación del gas ideal

P \times V = n \times R \times T\\V = \frac{n \times R \times T}{P} = \frac{2,4mol \times 62,4mmHg.L/mol.K \times 300K}{624mmHg} = 72 L

3 0
3 years ago
Which element most likely contains the greatest number of electrons?
weeeeeb [17]

Answer:

Hi.. Your answer is element A

5 0
3 years ago
What's the difference between saturated and unsaturated fatty acids?
xz_007 [3.2K]
Saturated fats<span> are solid at room temperature, while </span>unsaturated fats<span> are liquid at room temperature. This is because </span>saturated and unsaturated fats<span> differ in their chemical structures. </span>Saturated fats<span> have no double bond </span>between<span> molecules, which means there are no gaps and the </span>fat<span> is </span>saturated<span> with hydrogen molecules.</span>
6 0
4 years ago
Calculate the standard cell emf for the reaction: ClO3−(aq)+3Cu(s)+6H+(aq)→Cl−(aq)+3Cu2+(aq)+3H2O(l) Pt is used as an inert elec
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<u>Answer:</u> The standard EMF of the cell is 1.11 V

<u>Explanation:</u>

For the given chemical equation:

ClO_3^-(aq)+3Cu(s)+6H^+(aq.)\rightarrow Cl^-(aq.)+3Cu^{2+}(aq.)+3H_2O(l)

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To calculate the E^o_{cell} of the reaction, we use the equation:

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6 0
3 years ago
What will happen to the following equilibrium if Cl2
REY [17]

The following equilibrium will shift in the direction of the product:

<h3>Further explanation</h3>

Given

Reaction

4HCl + O₂ → 2H₂O + 2Cl₂

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Required

Equilibrium changes

Solution

Reaction = - action

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reducing the products ⇒Shifts in the direction of the products

Cl₂ as a product, so if Cl₂ is taken or reduced, the reaction will try to maintain system equilibrium by moving to the right (product formation) ⇒ Shift in the direction of the product:

7 0
3 years ago
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