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vazorg [7]
3 years ago
6

How much of a 10 M solution is needed to make 1 liter of all solution?

Chemistry
1 answer:
SashulF [63]3 years ago
4 0

Answer:

b is the answer 1000ml

please mark me brainlist

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a hot air balloon has a volume of 875L. what is the original temperature of the balloon if its volume changes to 955 L when heat
soldi70 [24.7K]

Answer:

using Charles law

v1/t1= v2/ t2

Explanation:

875/t1=955/56+273

t1= 329* 875/955

t1= 302.82k

4 0
3 years ago
A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and
sammy [17]

<u>Answer:</u> The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (S_8) = 0.800 g

M_{solute} = Molar mass of solute (S-8) = 256.52 g/mol

W_{solvent} = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m

  • <u>Calculation for freezing point of solution:</u>

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

or,

\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC

Hence, the freezing point of solution is 16.5°C

  • <u>Calculation for boiling point of solution:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

or,

\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC

Hence, the boiling point of solution is 118.2°C

5 0
3 years ago
Dioxybenzone is a compound found in sunscreen, and only contains carbon, oxygen, and hydrogen. Analysis of the compound found th
Zina [86]
Chemical formula that shows the totalnumber and kinds of atoms in a molecule,but not their structural arrangement. Forexample, the molecular formula of aspirinis C9H8O4. Compare empirical formulastructural formula .
contains 4.92% hydrogen and 26.18% oxygen. The molar mass of the compound is 244.25 g/mol




6 0
3 years ago
It takes 281.7 kJ of energy to remove 1 mole of electrons from the atoms on the surface of lithium metal. If lithium metal is ir
Alex17521 [72]

Answer:

The maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

Explanation:

We know that total energy

E = \frac{hc}{\lambda}  ------------ (1)

Here h = plank's constant = 6.62 × 10^{-34} J s

c = speed of light = 3 × 10^{8} \frac{m}{s}

\lambda = 261 nm = 261  × 10^{-9} m

Put all these values in equation (1) we get

E = 7.6   × 10^{-19} J

We know that

Total energy = Energy to remove an electron + K.E of electron

Energy to remove an electron = \frac{281.7 (1000)}{(6.023)10^{23} }

Energy to remove an electron = 4.67  × 10^{-19} J

K.E of electron = Total energy - Energy to remove an electron

K.E of electron = 7.6   × 10^{-19} -  4.67  × 10^{-19}

K.E of electron = 2.93 × 10^{-19} Joule

Therefore the maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

3 0
3 years ago
Deserts are only found near the equator.
Goshia [24]
True because it is warmer closer to the equator
8 0
3 years ago
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