MThe heat energy required to raise the temperature of 0.36Kg of copper from 22 c to 60 c is calculate using the following formula
MC delta T
m(mass)= 0.360kg in grams = 0.360 x1000 = 360 g
c(specific heat energy) = 0.0920 cal/g.c
delta T = 60- 23 = 37 c
heat energy is therefore= 360g x0.0920 cal/g.c x 37 c= 1225.44 cal
I check all of them. most of them correct but one
in question 6, the answer is the third choice. remember to find the neutrons, you take the atomic mass minus the atomic number. 38 - 18= 20
In a homogenous
mixture, sugar was the solute and water was the solvent. Solubility is the maximum
amount of a solute that dissolves in a given amount of solvent at a constant
temperature. Solutes
are more soluble in a given solvent at higher temperatures. Therefore, when
temperature increases, the solubility of the solute also increases.
<span>Moreover, the solubility of the substance ranges from infinitely soluble such
as alcohol in water, to poorly soluble like silver chloride in water and the
species that dissolves, the solute, can be another liquid, gas or a solid.</span>
Answer:
Explanation:
522 g
Explanation:
Your starting point here will be the balanced chemical equation for this combustion reaction
4
P
(s]
+
5
O
2(g]
→
2
P
2
O
5(s]
Notice that you have a
4
:
5
mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need
5
4
time more moles of oxygen gas.
Use phosphorus' molar mass to determine how many moles you have in that
93.0-g
sample
93.0
g
⋅
1mole P
30.974
g
=
3.0025 moles P
Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction
3.0025
moles P
⋅
5
moles O
2
4
moles P
=
3.753 moles O
2
Answer:It is false
Explanation:
I took a quiz with this question in it and I chose true but I got it wrong
