Should be chosen the bigger propability
0,6>0,4
Answer:
21
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
You have not provided the options to help us give you a specific answer.
If a quadratic function is written in the form
![f(x) = a {(x - h)}^{2} + k](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%20%7B%28x%20-%20h%29%7D%5E%7B2%7D%20%20%2B%20k)
Then (h,k) is the vertex, and 'a' is a constant.
For instance
![f(x) = 5 {(x - 1)}^{2} + 3](https://tex.z-dn.net/?f=f%28x%29%20%3D%205%20%7B%28x%20-%201%29%7D%5E%7B2%7D%20%20%2B%203)
has vertex at (2,3).
Also, an absolute function in the form
![g(x) = a |x - h| + k](https://tex.z-dn.net/?f=g%28x%29%20%3D%20a%20%20%7Cx%20-%20h%7C%20%20%2B%20k)
has vertex at (h,k).
This means
![g(x) = |x - 1| + 3](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%20%7Cx%20-%201%7C%20%20%2B%203)
also has vertex at (1,3).
I hope this explanation is helpful.
You need to use the cosine for this and this is how you do it.
Answer:
20
Step-by-step explanation:
you've got to do the inside parenthesis first then multiple with 3 and finally add 8