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Effectus [21]
3 years ago
15

One student begins in Cleveland, Ohio, and walks towards Buffalo, New York, a distance of 200 miles. She walks at the rate of 2.

5 miles per hour. Another student begins riding his bicycle in Cleveland and rides towards Buffalo at the rate of 11 miles per hour. The walking student begins her journey at 8:00 AM. The riding student starts 4 hours later.

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0
The problem did not have enough details.It seems like you want to know that  !st person leaves and 2nd person leaves; how long before they catch up together? These types of problems are called Uniform Motion or Rate-Time-Distance.There is a good video for you to watch.Similar to the problem you need help with. Yourmathgal channel on Youtube,she is a teacher.Have watched a lot of her videos.Watch the video on her channel called "Rate-Time-Distance Intro".It is 10:40 and she explains the 6 kinds of Uniform Motion problems.

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What is the first proportion? Someone please help, I have no idea what this means.
Olenka [21]

Answer:1 is called the first term of the proportion, 2 is the second term, 5 is the third, and 10, the fourth. We say that 5 corresponds to 1, and 10 corresponds to 2.

Step-by-step explanation:

1 is called the first term of the proportion, 2 is the second term, 5 is the third, and 10, the fourth. We say that 5 corresponds to 1, and 10 corresponds to 2.

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An urn contains 6 red balls, 8 green balls, and 10 white balls. If balls are selected one by one (without replacing them after t
PIT_PIT [208]

Answer:

0.43478

Step-by-step explanation:

From the information given:

The \  required  \ probability = P(1st ball = red) \times P(2nd ball = red) + P(1st ball = red) \times P(2nd ball = white)  + P(2nd ball = red) \times P(1st ball = white) + P(1st ball = white) \times P(2nd ball = white)

= \dfrac{6}{6+8+10}\times  \dfrac{5}{5+8+10} +  \dfrac{6}{6+8+10} \times  \dfrac{10}{5+8+10} +  \dfrac{10}{6+8+10} \times  \dfrac{6}{5+8+10} \times  \dfrac{10}{6+8+10} \times  \dfrac{9}{5+8+9}

=(\dfrac{6}{24}\times \dfrac{5}{23})+ (\dfrac{6}{24}\times \dfrac{10}{23}) +( \dfrac{10}{24}\times \dfrac{6}{23} ) + (\dfrac{10}{24}\times \dfrac{9}{23})

= 0.05434782609 + 0.1086956522  + 0.1086956522  + 0.1630434783

= 0.4347826088

≅ 0.43478

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All you have to do is divide 4 by 6.  
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