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Ivahew [28]
3 years ago
5

Classify triangle ABC by its sides if side AB = 6x, side AC = 4x + 6 and side BC = 8x + 3. The perimeter of triangle ABC is 63.

Show all your work.
Mathematics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

So the triangle ABC is an isosceles triangle

Step-by-step explanation:

By definition the perimeter of a triangle is equal to the sum of the lengths of its sides.

In this case we know that the perimeter is 63

The lengths of its sides depend on x.

AB = 6x\\AC = 4x + 6\\BC = 8x + 3

So:

6x + 4x + 6 + 8x + 3 = 63

Now we solve for the variable x.

6x + 4x + 6 + 8x + 3 = 63

18x + 9 = 63

18x = 54

x=\frac{54}{18}\\\\x=3

Therefore:

AB = 6(3)=18\\AC = 4(3)+6=18\\BC = 8(3) + 3=27

The triangle has two sides of equal length. The triangles that have two equal sides are the isosceles triangles.

So the triangle ABC is an isosceles triangle

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Step-by-step explanation:

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8 0
3 years ago
When it is operating properly, a chemical plant has a daily production rate that is normally distributed with a mean of 885 tons
-BARSIC- [3]

Answer:

<em>The test statistic Z = 1.844 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<em>Yes he is right</em>

<em>The manager claims that at least 95 % probability that the plant is operating properly</em>

Step-by-step explanation:

<u>Explanation</u>:-

Given data Population mean

                                           μ     = 885 tons /day

Given random sample size

                                          n = 60

mean of the sample

                                        x⁻  = 875 tons/day

The standard deviation of the Population

                                      σ = 42 tons/day

<em><u>Null hypothesis</u></em><em>:- H₀: </em>The manager claims that at least 95 % probability that the plant is operating properly

<u><em>Alternative Hypothesis :H₁</em></u>: The manager do not claims that at least 95 % probability that the plant is operating properly

<em>Level of significance</em> =  0.05

The test statistic

 Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

Z = \frac{875 -885}{\frac{42}{\sqrt{60} } }

Z = \frac{-10}{5.422} = -1.844

|Z| = |-1.844| = 1.844

<em>The tabulated value</em>

<em>                          </em>Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96<em></em>

<em>The calculated value Z = 1.844 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<u><em>Conclusion</em></u><em>:-</em>

<em>The manager claims that at least 95 % probability that the plant is operating properly</em>

<em></em>

<em></em>

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irga5000 [103]
X = -3 - 6i + yi
y = -3i - xi + 6
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