2 years ago

Find the set of values ofx for which y is zero inthe equation y=(x+2) (x-2).

1 answer:

Zolol [24]2 years ago

5 0

Answer:-2

Step-by-step explanation:put ur eaquation in the calculator and go to the table by pressing 2nd graph

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KiRa [710]

ANSWER

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

EXPLANATION

The given product is:

$( \sqrt{14} - \sqrt{3} )( \sqrt{12} + \sqrt{7} )$

We expand using the distributive property to obtain:

$\sqrt{14}( \sqrt{12} + \sqrt{7}) -\sqrt{3}( \sqrt{12} + \sqrt{7} )$

Extract the perfect squares to get:

$\sqrt{14}(2 \sqrt{3} + \sqrt{7}) -\sqrt{3}( 2\sqrt{3} + \sqrt{7} )$

Expand further to get;

$2 \sqrt{42} +7 \sqrt{2}- 2(3) - \sqrt{21}$

This simplifies to,

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

5 0

2 years ago

Find the set of values ofx for which y is zero inthe equation y=(x+2) (x-2).​