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Murljashka [212]

3 years ago

7

Which congruence theorems can be used to prove ΔABR ≅ ΔACR? Select three options

2 answers:

Mashcka [7]3 years ago

8 0

Answer:

SAS , ASA, SSS

Step-by-step explanation:

SAS , side A= side A . Angle B= Angle C, side R= side R

ASA, Angle A= Angle A . Side B= side C, Angle R= Angle R

SSS

side A= side A . Side B= side c, side R= side R

Leokris [45]3 years ago

7 0

Answer:

<h2>They are congruent by SAS postulate.</h2>

Step-by-step explanation:

Choice for this question are

HL
SAS
SSS
ASA
AAS

In the image attached, you can observe the pairs of triangles we are talking about. Notice that they are right triangles, which means the congruence postulates we could use are Hypothenuse-Leg, Leg-Leg, Leg-Angle and Hypothenuse Angle, however, this choices are not useful.

We know by given that

$AC \cong AB$ and $RC \cong RB$

We also know that $\angle B \cong \angle C$

So, we have two corresponding sides congruent, and the pair of corresponding angle formed by those sides are also congruent.

Therefore, by Side-Angle-Side

$\triangle ABR \cong \triangle ACR$

So, the right answer is SAS.

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Liula [17]

Answer:

B.

Step-by-step explanation:

The easiest way is to substitute 8 for x in the first equation,

5 0

3 years ago

Salsk061 [2.6K]

Answer:

a- 3 batches

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3 0

3 years ago

Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

6 0

3 years ago

Is 8 one tenths of 80

Otrada [13]

Yeah 8 is 1/10th of 80.

6 0

3 years ago

Read 2 more answers

If you make $450 a month but 15% is held out of each paycheck for Social Security and taxes how much do bring home?

aksik [14]

To solve this question make an equation

450 x 0.15 = X

0.15 = the percentage taken out of the paycheck

67.5 = Social Security Taxes

450 - 67.5

= $382.5

Or the easier way if you want it straight away

450 x 0.85 = $382.5

0.85 = percentage taken home

3 0

3 years ago