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statuscvo [17]
3 years ago
13

4. Suppose an investment of $s1.800 doubles in value every 7 years. How much is the investment worth after 42 years?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

we are given

initial amount =1800

so,

P=1800

doubles in value every 7 years

so, we can find function

A=P(2)^{\frac{t}{7} }

now, we can plug P=1800

A=1800(2)^{\frac{t}{7} }

now, we can plug t=42

A=1800(2)^{\frac{42}{7} }

A=115200.............Answer

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