Answer:
Step-by-step explanation:
a)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,r =50
rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854
area growing 7854 cm2/s
b)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,A =64
pi r^2 =64
=>r =8/√pi
rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98
area growing 708.98 cm2/s
Answer:
x = 95
Step-by-step explanation:
The total degree of a circle is 360. The twp arcs on each side of the parallel lines are equal.
Subtract 135 and 35 from your total
<em>360 - 135 - 35 = 190</em>
Divide your answer by 2
<em>190 ÷ 2 = 95</em>
It would be 5x?=60 because to find "?" you would need to divide 60 and 5. Since Hector earned 5 times what he did last week it would be modeled by 5 times "?"
Answer:
7 notepads
Step-by-step explanation:
5 + 3x = 26
Subtract constant (5)
3x = 21
Divide by coefficient (3)
x=7
Answer:
<em>The answer is Hence Proved</em>
Step-by-step explanation:
Given that CB║ED , CB ≅ ED
To prove Δ CBF ≅ Δ EDF
This means that the length of CB is equal to ED
As CB║ED The following conditions satisfies when a transversal cut
two parallel lines
- ∠ EDF = ∠ FBC ( Alternate interior points )
- ∠ DEF = ∠ FCB ( Alternate interior points )
∴ Δ CBF ≅ Δ EDF ( By ASA criterion)
The Δ CBF is congruent to Δ EDF By ASA criterion .
<em> Hence proved </em>
