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Maurinko [17]
4 years ago
10

A candy bar box is in the shape of a triangular prism. The volume of the box is 1,200 cubic centimeters. Part A: What is the hei

ght of the box? Show your work. (5 points) Part B: What is the approximate amount of cardboard used to make the sides of the candy box? Explain how you got your answer. (5 points)

Mathematics
2 answers:
Rus_ich [418]4 years ago
5 0
Hello!

A) 10 cm

As we can see in the diagram, the height of the prism is 10 cm.

B) 850 cm

To find the answer we need to find the surface area of the candy box. To do so you add up the area of each face, as seen below.

65(triangle)+65 (triangle)+200 (base)+260(side)+260(side).=850.

I hope this helps!
never [62]4 years ago
3 0

Answer:

I dont know

Step-by-step explanation:

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Which expression is equivalent to -3.5(4x – 3)? A. -3.9x – 3.2 B. -3.9x + 3.2 C. -14x + 10.5 D. -14x – 10.5
romanna [79]

Answer:

I do not know

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Calculate the average rate of change for the given function, from x = −3 to x = 7.
emmainna [20.7K]

Answer:

The average rate of change for the given function, from x = −3 to x = 7 will be:

  • Average rate = -5

Step-by-step explanation:

Given the table

x                      f(x)

-3                     50

3                      10

7                       0

As the interval is from x = -3 to x = 7.

so

at x₁ = -3, f(x₁) = 50

at x₂ = 7,  f(x₂) = 0

Using the formula to determine the average rate of change at which the total cost increases will be:

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                       = [0 - 50] / [7-(-3)]

                      = [-50] / [7+3]

                      = -50 / 10

                      = -5

Therefore, the average rate of change for the given function, from x = −3 to x = 7 will be:

  • Average rate = -5
6 0
3 years ago
Is y=1/100(31)x a exponential decay?
statuscvo [17]
No;

it is exponentially always increasing
7 0
3 years ago
Here, thankyou!!!!!!!
FromTheMoon [43]

Answer:

Perimeter of i - 22CM

Area of i - 13CM^2

Perimeter of ii -38CM

Area of ii -66CM^2

Perimeter of iii -30CM

Area of iii- 42CM^2

Perimeter of iv - 50CM

Area of iv- 126CM^2

Step-by-step explanation:

SHAPE I:

PERIMETER = S + S + S + S + S +S

= 7 + 1 + 5 +3 +4 +2

= 22CM

AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2

Total = 8 + 5 = 13cm^2

SHAPE II:

PERIMETER = S + S + S + S + S +S

= 4 + 4 +5 + 6 + 9 + 10

= 38 CM

AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2

Total = 50+16 =66 cm^2

SHAPE III:

PERIMETER = S + S + S + S + S +S

= 9 + 2 + 3 + 4 + 6 + 6

= 30CM

AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2

Total = 36 + 6 =42 cm^2

SHAPE IV:

PERIMETER = S + S + S + S + S +S

= 9 + 10 + 4 + 6 + 6 + 15

= 50 CM

AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2

Total = 90 + 36 = 126cm^2

HOPE THIS HELPED

6 0
3 years ago
How to solve exterior angle for right triangle?
denis23 [38]
Attached the solution and work.

5 0
3 years ago
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