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Alborosie
2 years ago
5

Point L is located at (-3,-6) where is L after a reflection over the y-axis

Mathematics
1 answer:
ohaa [14]2 years ago
3 0

9514 1404 393

Answer:

  L'(3, -6)

Step-by-step explanation:

The reflection over the y-axis is modeled by the transformation ...

  (x, y) ⇒ (-x, y)

  L(-3, -6) ⇒ L'(3, -6)

Point L is located at (3, -6) after the reflection from the 3rd quadrant to the 4th quadrant across the y-axis.

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Choose the equation that models the word problem. A football team won 33 games in the first three seasons. The team played a tot
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C. It should be equal to 48 because that is the total number of games. It should be +33 so you can subtract 33 from both sides to see how many games the football team lost.
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Which phrase matches the algebraic expression below?<br> 2(x - 7) +10
Ierofanga [76]

Answer:

2 times the difference of x minus 7 plus 10

Step-by-step explanation:

When dealing with equations, you ALWAYS do the parentheses first. The first relationship x and 7 are going to have is being subtracted from eachother. Once you do that, you can do the rest of the equation. Hope this helps!

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3 years ago
A pool area includes 68 square meters of paving at $32 per square meter. What is the total cost of paving?
Zielflug [23.3K]

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Use Multiplication.

\small \sf   \:  \:  \:   \:   \: = 32 \times 68 \\   \small \sf =  \color  {lightgreen} \pmb  { 2176}

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\small \sf \pmb \:  \color{gray}{-ItzCamero}

7 0
1 year ago
Read 2 more answers
A shopkeeper has 2425 boxes of 24 pencils each. How many pencils do all the boxes have in all?​
BabaBlast [244]

Answer:A shopkeeper has 2425 boxes of 24 pencils each. How many pencils do all the boxes have in all?​

Step-by-step explanation:

5 0
2 years ago
A cannonball was launched with an initial upward velocity of 55 feet per second from a tower 28 feet off the ground. The height
Ann [662]

Answer:

The value of b is 55

The value of c is 28

The expression for the height of the ball at time t is h(t) = -16t² + 55t + 28

Step-by-step explanation:

* Lets discus the situations in the problem

- The ball was lunched up from a tower of height 28 feet above

  the ground

∴ The initial height = 28 feet ⇒ (initial means time is zero)

- The ball launched with an initial velocity 55 feet/second

∴ The initial velocity = 55 feet/second ⇒ (at t = 0)

- The equation of the height of the ball after t second is:

  h = ut + 1/2 at² + hi, where u is the initial velocity, a is the acceleration of

  gravity, t is the number of seconds since the ball was lunched

  hi is the initial height which the ball was lunched from it  and h is the

  height above the ground

∵ The ball was lunched up

∴ The gravity acceleration is -16 feet/second²

∵ The initial velocity is upward

∴ u = 55 feet/second

∵ The tower is 28 feet above the ground

∴ hi = 28 feet

- Substitute these values in the equation

∴ h = 55t + 1/2(-32)t² + 28 ⇒ simplify

∴ h = 55t - 16t² + 28 ⇒ start with t²

∴ h = -16t² + 55t + 28

* Now compare between the two equation

∵ h = -16t² + bt + c

∵ h = -16t² + 55t + 28

∴ b = 55 ⇒ coefficient of t

∴ c = 28

∴ h(t) = -16t² + 55t + 28

8 0
3 years ago
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