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2 years ago

Point L is located at (-3,-6) where is L after a reflection over the y-axis

Mathematics

1 answer:

ohaa [14]2 years ago

3 0

9514 1404 393

Answer:

L'(3, -6)

Step-by-step explanation:

The reflection over the y-axis is modeled by the transformation ...

(x, y) ⇒ (-x, y)

L(-3, -6) ⇒ L'(3, -6)

Point L is located at (3, -6) after the reflection from the 3rd quadrant to the 4th quadrant across the y-axis.

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Answer:

The given three dimensional is triangle prism On3 of the bases is triangle KML Edge JM intersects edge LM at point M

Step-by-step explanation:

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2 years ago

In ΔLMN, \overline{LN} LN is extended through point N to point O, m∠NLM = (x+1)^{\circ}(x+1) ∘ , m∠LMN = (x+15)^{\circ}(x+15) ∘

mixer [17]

Answer:

26 degree

Step-by-step explanation:

We are given that in triangle

$\angle NLM=(x+1)^{\circ}$

$\angke LMN=(x+15)^{\circ}$

$\angle MNO=(4x+6)^{\circ}$

$\angle MNO+\angle MNL=180^{\circ}$

By using linear pair angles property

$\angle MNL=180-\angle MNO=180-(4x+6)$

$\angle MNL+\angle NLM+\angle LMN=180^{\circ}$

By using triangle angles sum property

$180-(4x+6)+x+15+x+1=180$

$2x+16=180-180+4x+6$

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$2x=10$

$x=\frac{10}{2}=5$

Substitute the value

$\angle MNO=4(5)+6=20+6=26^{\circ}$

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3 years ago