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Rasek [7]
3 years ago
8

How do you calculate the number of formula units for 6.82 X 10 -6 mol of lead(II) nitrate.

Chemistry
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:345

Explanation:

32456

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What role in a factory does the cell membrane play
Vilka [71]
The plasma membrane
7 0
3 years ago
Chemistry help! Please zoom in to see better ​
sergeinik [125]

Answer:

82.04g

Explanation:

To solve this problem, you need to find the molar mass of HCl, which is the sum of the molar mass of H plus the molar mass of Cl. The molar mass of H is 1.008g/mol while the molar mass of Cl is 35.45g/mol. Thusly the molar mass of HCl is 36.458g/mol. You have 2.25 moles of HCl, so multiply the number of moles by the molar mass to get the mass in g. In this case it is 2.25mol * 36.458g/mol = 82.04g.

If I helped, a brainliest would be greatly appreciated!

3 0
3 years ago
If excess sodium is added to 0.10 L of 1.00 M hydrochloric acid solution, how many moles of NaCl is formed?
Ksenya-84 [330]

Answer:

=> 0.10 moles

Explanation:

The question is asking us to find the moles of NaCl cid formed.

We have been provided with;

0.10 L of 1.0 M NaOH.

We know that mole ratio of the reaction is 1:1 and also the molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.

This means that;

1.0 M is contained in 1.0 L.

X mol is contained in 0.10 L

x \: mol \:  =  \frac{0.1 \times 1.0}{1.0}  \\  = 0.10 \: mol

= 0.10 moles of NaCl formed

8 0
2 years ago
Given the reaction for the corrosion of aluminum: 4 Al + 3 O2 --> 2 Al2O3, which half-reaction correctly represents the oxida
Pavel [41]

Answer:

Option B, Al --> Al3+ + 3e-

Explanation:

Oxidation is defined as the process of losing electron by a molecule, atom or anion  thereby acquiring oxidation state i.e the positive charge. Reduction on the other hand is the process in which an atom, ion or molecule gains electron and gains negative charge on it.  

For example – In the reaction, H2 + F2 → 2 HF, hydrogen is oxidized H2 → 2 H+ + 2 e-  as it looses electron while fluorine is being reduced F2 + 2 e- → 2 F-

This is happening in the option B

5 0
3 years ago
8) what is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine
Novay_Z [31]
43.97/12.01=3.661=2
10.51/1.01=10.406=5
39.52/19.00=2.075=1
C2H5F
7 0
3 years ago
Read 2 more answers
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