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zlopas [31]
3 years ago
11

Write down the steps which correctly describe the steps required to decide whether or not a precipitate forms when two aqueous s

olutions are mixed.
Chemistry
1 answer:
Readme [11.4K]3 years ago
7 0

The correct question is as follows.

place the steps required to determine whether or not a precipitate forms when two solutions are mixed in the correct order.

-consider possible cation-anion combinations

-note the ions present in the reactions

-use the solubility rules to determine whether or not either of the combinations gives an insoluble salt

Explanation:

A precipitate is an insoluble substance formed due to chemical reaction between two aqueous solutions. But it is not necessary that two aqueous solutions will always give an insoluble solid substance on chemical reaction with each other.

For e.g. NaCl(aq) + AgNO_3(aq) \rightarrow NaNO_3(aq) + AgCl(s)

Here, AgCl is the precipitate formed.

Hence, correct steps that are required to decide whether or not a precipitate forms when two aqueous solutions are mixed:

1). note the ions present in the reactants

2). consider possible cation-anion combinations

3). use the solubility rules to determine whether or not either of the combinations gives an insoluble salt

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What is the molarity of 40ml of NaOH if it takes 25ml of 0.5 molar HCl to neutralize it?
Oksanka [162]

Answer:

Molarity of 40 ml of NaoH is 0.3125 mL

Explanation:

As we know  

Molarity of acid *  volume of acid = molarity of base * volume of base

Substituting the given values, we get  

0.5 * 25 = X* 40 \\X = \frac{0.5*25}{40} \\X = 0.3125

Molarity of 40 ml of NaoH is 0.3125 mL

6 0
3 years ago
Sodiun atom, potassium atom, and cesium atoms have the same ?
Tpy6a [65]
Sodium atom , potassium atom and cesium atom have the same group number which is group 1
3 0
3 years ago
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N2(g) + 2H(g) -> N2 H4(g) What are the volumes of N2 gas and H2 gas required to form 28.5 grams of N2 H4 at 30'C and 1.50 atm
FromTheMoon [43]

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

6 0
3 years ago
indicate if the following statements are true or false for a standard galvanic cell. oxidation occurs at the anode reduction occ
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In contrast to an Anode, a Cathode is an electrode pole in an electrochemical cell that is polarized if this pole is positively charged (so that an electric current will flow out of it, or the movement of electrons will enter this pole).

In galvanic cells or power plants (batteries), the anode is the negative pole. The electrode will release electrons towards the circuit and hence an electric current flows into this electrode and makes it an anode and negative.

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Nostrana [21]
Nuclear hope this helps

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