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zlopas [31]
3 years ago
11

Write down the steps which correctly describe the steps required to decide whether or not a precipitate forms when two aqueous s

olutions are mixed.
Chemistry
1 answer:
Readme [11.4K]3 years ago
7 0

The correct question is as follows.

place the steps required to determine whether or not a precipitate forms when two solutions are mixed in the correct order.

-consider possible cation-anion combinations

-note the ions present in the reactions

-use the solubility rules to determine whether or not either of the combinations gives an insoluble salt

Explanation:

A precipitate is an insoluble substance formed due to chemical reaction between two aqueous solutions. But it is not necessary that two aqueous solutions will always give an insoluble solid substance on chemical reaction with each other.

For e.g. NaCl(aq) + AgNO_3(aq) \rightarrow NaNO_3(aq) + AgCl(s)

Here, AgCl is the precipitate formed.

Hence, correct steps that are required to decide whether or not a precipitate forms when two aqueous solutions are mixed:

1). note the ions present in the reactants

2). consider possible cation-anion combinations

3). use the solubility rules to determine whether or not either of the combinations gives an insoluble salt

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What is ionisation enthalpy?​
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Which of the following pairs lists a substance that can neutralize H2SO4 and the salt that would be produced from the reaction?
Bogdan [553]

The second option only.

  • LiOH, Li₂SO₄.
<h3>Explanation</h3>

A base neutralizes an acid when the two reacts to produce water and a salt.

Sulfuric acid H₂SO₄ is the acid here. There are more than one classes of bases that can neutralize H₂SO₄. Among the options, there are:

Metal hydroxides

  • Ca(OH)₂ and
  • LiOH.

Metal hydroxides react with sulfuric acid to produce water and the sulfate salt of the metal.

\text{Ca}(\text{OH})_{\bf 2}+\text{H}_2\text{SO}_4 \to \textbf{Ca}\textbf{SO}_{\bf 4} +{\bf 2}\;\text{H}_2\text{O}.

The formula for calcium sulfate \text{CaSO}_4 in option A is spelled incorrectly. Why? The charge on each calcium \text{Ca}^{2+} is +2. The charge on each sulfate ion {\text{SO}_4}^{2-} is -2. Unlike \text{Li}^{+} ions, it takes only one \text{Ca}^{2+} ion to balance the charge on each {\text{SO}_4}^{2-} ion. As a result, \text{Ca}^{2+} and {\text{SO}_4}^{2-} ions in calcium sulfate exist on a 1:1 ratio.

2\;\text{LiOH} +\text{H}_2\text{SO}_4 \to \text{Li}_2\text{SO}_4 + 2\;\text{H}_2\text{O}.

Ammonia, NH₃

Ammonia NH₃ can also act as a base and neutralize acids. NH₃ exists as NH₄OH in water:

\text{NH}_3 + \text{H}_2\text{O} \to \textbf{NH}_{\bf 4}\text{OH}.

The ion {\text{NH}_4}^{+} acts like a metal cation. Similarly to the metal hydroxides, NH₃ (or NH₄OH) neutralizes H₂SO₄ to produce water and a salt:

2\;\textbf{NH}_{\bf 4}\text{OH}+ \text{H}_2\text{SO}_4 \to (\textbf{NH}_{\bf 4})_2\text{SO}_4+2\;\text{H}_2\text{O}.

The formula of the salt (NH₄)₂SO₄ in the fourth option spelled the ammonium ion incorrectly.

As part of the salt (NH₄)₂SO₄, the ammonium ion NH₄⁺ is one of the products of this reaction and can't neutralize H₂SO₄ any further.

7 0
3 years ago
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