The more particles (ions or molecules) that you can put into solution, the lower the freezing point.
the answer is E. 2.0 M nacl
Wouldn't it be just dubble the amount witch would be 300.0g water
Answer: You can have a loop in a series circuit than a parallel circuit
Explanation: You can have a loop! How is this loop helpful? I don't know, I have no idea how this would be useful. Ah! maybe you can have many things activate sequentially like a lightshow. You can make a series circuit and it will just repeat. You can repeat a lightshow. I don't know what else you can do.
Answer:
- The answer is the concentration of an NaOH = 1.6 M
Explanation:
The most common way to solve this kind of problem is to use the formula
In your problem,
For NaOH
C₁ =?? v₁= 78.0 mL = 0.078 L
For H₂SO₄
C₁ =1.25 M v₁= 50.0 mL = 0.05 L
but you must note that for the reaction of NaOH with H₂SO₄
2 mol of NaOH raect with 1 mol H₂SO₄
So, by applying in above formula
- (C₁ * 0.078 L) = (2* 1.25 M * 0.05 L)
- C₁ = (2* 1.25 M * 0.05 L) / (0.078 L) = 1.6 M
<u>So, the answer is the concentration of an NaOH = 1.6 M</u>
