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Stells [14]
2 years ago
13

In the PhET simulation window, click the radio button labeled Mystery in the Blocks menu on the right-hand side of the screen. U

sing the scale and water tank, determine the mass of each block using the scale and the volume of each block by submerging it in water. Use these values to calculate the density. Rank the mystery blocks in order from least dense to most dense. Rank from least dense to most dense. To rank items as equivalent, overlap them.
Tank A 103.38 L, B 100.64 L, C 104.08 L, D 103.10 L, E 101.00 L

Scale A 65.14 kg, B 0.64 kg, C 4.08 kg, D 3.10 kg, E 3.53 kg
Chemistry
1 answer:
Yuliya22 [10]2 years ago
4 0

Answer:

B, D, E, C, A

Explanation:

We have 5 blocks with their respective masses and volumes.

Block            Mass            Volume

  A                65.14 kg       103.38 L

  B                0.64 kg         100.64 L

  C                4.08 kg         104.08 L

  D                3.10 kg          103.10 L

  E                 3.53 kg         101.00 L

The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V

ρA = 65.14 kg / 103.38 L = 0.6301 kg/L

ρB = 0.64 kg / 100.64 L = 0.0064 kg/L

ρC = 4.08 kg / 104.08 L = 0.0392 kg/L

ρD = 3.10 kg / 103.10 L = 0.0301 kg/L

ρE = 3.53 kg / 101.00 L = 0.0350 kg/L

The order from least dense to most dense is B, D, E, C, A

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Answer:

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3 0
3 years ago
What is the name of the binary compound that has the formula k2s?
kozerog [31]

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8 0
3 years ago
A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How
IrinaK [193]

Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 783J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 254 g

\Delta T = change in temperature = T_2-T_1=(23.73-26.01)=-2.28^oC

Now put all the given values in the above formula, we get:

q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]

q=-4208.28J=-4.81kJ

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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3 years ago
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Answer:

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Explanation:

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2 years ago
An 85.0 g sample of iron requires 954 J of heat to raise its temperature 25.0°C. What is the specific heat of the iron? \
Zanzabum

Answer:448.9 J/kg °C

Explanation:

See attached photo

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3 years ago
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