Question

a) Work out the next term in this sequence. 4 12 16 b) Describe the rule for continuing this sequence. 44 41 38 35 32 c) The sequences in parts (a) and (b) continue. Work out a number that is in both sequences.

Answer 1

Answer:

1. Next sequence = 20

2. Tn = 47 - 3n

3. Common number: 32

Step-by-step explanation:

Given

Sequence 1: 0, 4, 8, 12, 16

Sequence 2: 44, 41, 38, 35, 32

a. Write out the next sequence in (1)

The pattern followed by sequence 1 is that, each successive sequence is and addition of 4 to the previous sequence..

See observation below

4 = 0 + 4

8 = 4 + 4

12 = 8 + 4

16 = 12 + 4

Definitely, the next sequence will be 4 + the previous sequence.

Next sequence = 16 + 4

Next sequence = 20

2. The rule for continuing sequence 2

It'll be observed that sequence 2 follows an arithmetic progression.

To get the rule for continuing the sequence, the following data are needed.

I. The first term of the sequence.

This is often represented by letter a.

a = 44

II. The common difference.

This is the difference between two successive sequence

This is often represented by letter d.

d = 41 - 44 = -3

Or

d = 38 - 44 = -3

Using the arithmetic progression formula

Tn = a + (n - 1)d

By substituting 44 for a and -3 for d.

Tn = 44 + (n - 1)(-3)

Tn = 44 - 3n + 3

Tn = 44 + 3 - 3n

Tn = 47 - 3n

Hence, the rule for continuing the sequence is 47 - 3n where n is the current term of the sequence

III. Work out a number in common in both sequence

It'll be observed that the visible data of sequence 2 are bigger than that of sequence 1.

To get a common number, we have to extend sequence 1 until we arrive at a common number in both sequence

Sequence 1: 0, 4, 8, 12, 16

This becomes

Sequence 1: 0, 4, 8, 12, 16, 20, 24, 28, 32.....

32 is common in sequence (1) and (2).

If the sequence is extended, we'll arrive at another common number. But we have to stop, since we've arrived at a common number.