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Elanso [62]
3 years ago
5

A jug contains 6 qt of killa kola. kyle drank 3/10 of the jug. how much did he drink

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer:

Kyle drank 1.8 quarts of the jug.

Step-by-step explanation:

The quantity that Kyle drank from the jug is to equivalent to the product of the volume of the jug and portion that Kyle used. That is:

V_{dr} = \frac{3}{10}\cdot V_{jug}

Where:

V_{dr} - Volume that Kyle drank, measured in quarts.

V_{jug} - Volume of the jug, measured in quarts.

If V_{max} = 6\,qt, the volume drank by Kyle is:

V_{dr} = \frac{3}{10}\cdot (6\,qt)

V_{dr} = 1.8\,qt

Kyle drank 1.8 quarts of the jug.

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Point R is on line segment QS. Given RS = 13 and QS = 20, determine the length of QR
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3 years ago
The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an
Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w  feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

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Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = \dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, w = \dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}

Or, w = \dfrac{-11\pm \sqrt{473}}{2}

or, w = \dfrac{-11\pm 21.7}{2}

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

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