Answer:
First, you have to rewrite the question in a way to isolate your Y. This means moving the -3 over to the other side.
Y = 2(x+1) + 3
Now, you should multiply the 2 out in the parenthesis.
Y=2x+2+3
Now, combine like terms! In this case, your like terms are 2 and 3.
Y=2x + 5
Because there are no more like terms, and Y is completely isolated, Y=2x + 5 is your answer!
The given plane has normal vector
Scaling <em>n</em> by a real number <em>t</em> gives a set of vectors that span an entire line through the origin. Translating this line by adding the vector <2, 1, 1> makes it so that this line passes through the point (2, 1, 1). So this line has equation
This line passes through (2, 1, 1) when <em>t</em> = 0, and the line intersects with the plane when
which corresponds the point (3, -1, 1) (simply plug <em>t</em> = 1 into the coordinates of 
).
So the distance between the plane and the point is the distance between the points (2, 1, 1) and (3, -1, 1):
Answers:
- Box 1: Greater than
- Box 2: Less than
So,
- If any values in the data set are <u>greater than</u> the upper boundary, then those values are upper outliers.
- If any values in the data set are <u>less than</u> the lower boundary, then those values are lower outliers.
The general rule is that the upper boundary is found computing Q3+1.5*IQR, where IQR is the interquartile range. Recall that IQR = Q3-Q1. The Q1 and Q3 are the first and third quartiles respectively.
Another rule is that the lower boundary is found by computing Q1 - 1.5*IQR
On a box and whisker plot, outliers are points that are not connected to the main plot itself. You can think of them as islands far from the mainland.
Answer:
angle 4
Step-by-step explanation:
Angle 4 is the opposite of angle 5, if you flip the paper upside down, you'll see that it is the same
