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Irina-Kira [14]
2 years ago
7

A commercial building contractor is trying to decide which of two projects to commit her company to. Project A will yield a prof

it of $50,000 with a probability of 0.6, a profit of $80,000 with a probability of 0.3, and a profit of $10,000 with a probability of 0.1. Project B will yield a profit of $100,000 with a probability of 0.1, a profit of $64,000 with a probability of 0.7, and a loss of $20,000 with a probability of 0.2. Find the expected profit for each project. Based on expected values, which project should the contractor choose? OA. O B. Project A: $46,666 Project A: $55,000 Project B: $50,800 Contractor should choose project A Project B: $48,000 Contractor should choose project A O C. Project A: $55,000 O D. Project A: $46,000 Project B: $58,800 Contractor should choose project B Project B: $50,800 Contractor should choose project B
Mathematics
1 answer:
Alexxandr [17]2 years ago
3 0

Answer:

  Project A: $55,000 Project B: $50,800 Contractor should choose project A

Step-by-step explanation:

The expected value of the project is the sum of products of profit and its probability:

In thousands, ...

  A:  (50×0.6) +(80×0.3) +(10×0.1) = 30 +24 +1 = 55 . . . thousand

  B:  (100×0.1) +(64×0.7) +(-20×0.2) = 10 +44.8 -4 = 50.8 . . . thousand

__

The contractor should choose Project A based on the expected value of profit.

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The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA ba
PSYCHO15rus [73]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.

Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.

xbar = $1,465,752

SD = $1,346,046.2

lower bound of confidence interval ________

upper bound of confidence interval _______

Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.

xbar = $1,371,191

SD = $1,130,666.5

lower bound of confidence interval _________

upper bound of confidence interval. ________

Answer:

Question 1:

lower bound of confidence interval = $1,124,027

upper bound of confidence interval = $1,807,477

Question 2:

lower bound of confidence interval = $1,081,512

upper bound of confidence interval = $1,660,870

Step-by-step explanation:

Question 1:

The sample mean salary of 62 couches is

 \bar{x} = 1,465,752

The standard deviation of mean salary is

 s = 1,346,046.2

The confidence interval for the mean salary of all basketball coaches is given by

 $ CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where \bar{x} is the sample mean, n is the sample size, s is the sample standard deviation and  t_{\alpha/2} is the t-score corresponding to a 95% confidence level.  

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 62 - 1 = 61

From the t-table at α = 0.025 and DoF = 61

t-score = 1.999

So the required 95% confidence interval is  

CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\

Question 2:

After removing the Coach Krzyzewski's salary from the data

The sample mean salary of 61 couches is

\bar{x} = 1,371,191

The standard deviation of the mean salary is

s = 1,130,666.5

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 61 - 1 = 60

From the t-table at α = 0.025 and DoF = 60

t-score = 2.001

So the required 95% confidence interval is  

CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (\frac{1,130,666.5}{\sqrt{61} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (144767 ) \\\\CI = 1,371,191 \pm 289,678.8 \\\\LCI = 1,371,191 - 289,678.8 = 1,081,512 \\\\UCI = 1,371,191 + 289,678.8 = 1,660,870\\\\

6 0
3 years ago
61.7 is what percent of 64? Round to the nearest thousandth.
scoundrel [369]

Answer:

96.406%

Step-by-step explanation:

(61.7 ÷ 64) x 100 = 96.40625 = 96.406% (nearest hundredth)

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2 years ago
How to solve this? I'm new to it
Elodia [21]

Answer:

2 = 65

1= 115

Step-by-step explanation:

angles 2 and 65° are equal

so input that in for 2

then subtract it by 180°

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Will mark brainliest <br> thank you!
Mashcka [7]

Answer:

the answer is D 23/27 cars

Step-by-step explanation:

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Rods mother is 3 years more than 4 times as old as Rod . Their combined age is 33 . How old is Rod
marshall27 [118]
3 + 4x = 33
-3 on both sides
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x = 7.5

Answer:
Rod is 7 1/2 years old
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3 years ago
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