Answer:
- The equation that represent the cost C of renting a car and driving x miles is C = $39.11 + $0.50x
- $130 can travel 181.32 miles
Step-by-step explanation:
From the question, a rental company rents a luxury car at a daily rate of 39.34 $ plus $.50 per mile, that is
$0.50 is added to the initial $39.34 for every mile.
The equation that represent the cost C of renting a car and driving x miles is
C = $39.34 + $0.50x
Now, to determine how many miles 130$ can travel,
we will put C = $100, and determine x in the above equation
$130 = $39.34 + $0.50x
$130 - $39.34 = $0.50x
$90.66 = $0.50x
x = $90.66/$0.50
x = 181.32
Hence, $130 can travel 181.32 miles
Answer:
C
Step-by-step explanation:
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Answer:
4
Step-by-step explanation:
5-1=4
The total revenue of the function is the product of the quantity and the price
The total revenue in terms of P is TR = 20P - 0.01P^2
<h3>How to determine the total revenue?</h3>
The demand and the cost functions are given as:
Quantity function, Q = 20 - 0.01P
Cost function, C(Q)=60+6Q
The total revenue is calculated as:
TR = Q * P
Substitute Q = 20 - 0.01P in the above equation
TR = P * [20 - 0.01P]
Evaluate the product
TR = 20P - 0.01P^2
Hence, the total revenue in terms of P is TR = 20P - 0.01P^2
Read more about total revenue at:
brainly.com/question/25623677
