Answer:
The lower bound of a 99% C.I for the proportion of defectives = 0.422
Step-by-step explanation:
From the given information:
The point estimate = sample proportion 


= 0.55
At Confidence interval of 99%, the level of significance = 1 - 0.99
= 0.01

Then the margin of error 



E = 0.128156
E ≅ 0.128
At 99% C.I for the population proportion p is: 
= 0.55 - 0.128
= 0.422
Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422
Answer: 0.0007
Step-by-step explanation:
6/8654
Your answer is D because 10*2 is 20 and 6*2 is 12 so 12 out of the next 20 customers will purchase a sandwich.
The gcf of both is 11 so it would be 9+4q
Answer:
The answer is, The student added only three of the five faces.
Step-by-step explanation:
Hoped it help Have a great day :)