Question

find the amount and the compound interest on rupees 10000 for 2 years at 5% per annum compounded annually​

Answer 1

Answer:

11025

Step-by-step explanation:

100+5÷100=1.05 squared

10000x1.05squared=11025

Answer 2

Answer:

Amount = 11205

CI = 1205

Step-by-step explanation:

$a = p(1 + \frac{r}{n} ) {}^{nt}$

Here,

p = 10000

r = 5% = 5/100 = 0.05

n = 1

t = 2

$a = 10000(1 + \frac{0.05}{1} ) {}^{1 \times 2}$

$a = 10000(1.05) {}^{2}$

$a = 10000(1.1025)$

$a = 11205$

C.I = a - p

C.I = 11205 - 10000

C.I = 1205