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3 years ago

find the amount and the compound interest on rupees 10000 for 2 years at 5% per annum compounded annually

Mathematics

2 answers:

mr Goodwill [35]3 years ago

3 0

Answer:

11025

Step-by-step explanation:

100+5÷100=1.05 squared

10000x1.05squared=11025

Oksana_A [137]3 years ago

3 0

Answer:

Amount = 11205

CI = 1205

Step-by-step explanation:

$a = p(1 + \frac{r}{n} ) {}^{nt}$

Here,

p = 10000

r = 5% = 5/100 = 0.05

n = 1

t = 2

$a = 10000(1 + \frac{0.05}{1} ) {}^{1 \times 2}$

$a = 10000(1.05) {}^{2}$

$a = 10000(1.1025)$

$a = 11205$

C.I = a - p

C.I = 11205 - 10000

C.I = 1205

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Answer: Choice D) set of even integers

=======================================================

Explanation:

U = universal set = {all positive integers} = {1, 2, 3, 4, 5, ...}

A = {stuff in set U that is odd} = {1, 3, 5, 7, 9, ...}

$A^c$ = {stuff in set U but NOT from set A} = {2, 4, 6, 8, ...}

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Therefore, we go for choice D as our final answer.

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3 years ago

find the amount and the compound interest on rupees 10000 for 2 years at 5% per annum compounded annually​

find the amount and the compound interest on rupees 10000 for 2 years at 5% per annum compounded annually