What is 2 x 40/25<br> Two times forty over twenty-five

Lines that meet or cross each other to form square corners are called ______.

Viefleur [7K]

The lines that intersect to form square corners that are right angles are called: C. perpendicular lines.

<h3>What are Perpendicular Lines?</h3>

Perpendicular lines are lines that intersect each other at a point and forms for square corners that are right angles at that point of intersection.

An example of perpendicular lines is shown in the image attached below.

Thus, the lines that meet to form right angles are called: C. perpendicular.

Learn more about perpendicular lines on:

brainly.com/question/1202004

#SPJ1

5 0

2 years ago

Consider the initial value problem y′+5y=⎧⎩⎨⎪⎪0110 if 0≤t<3 if 3≤t<5 if 5≤t<[infinity],y(0)=4. y′+5y={0 if 0≤t<311 i

rosijanka [135]

It looks like the ODE is

$y'+5y=\begin{cases}0&\text{for }0\le t$

with the initial condition of $y(0)=4$ .

Rewrite the right side in terms of the unit step function,

$u(t-c)=\begin{cases}1&\text{for }t\ge c\\0&\text{for }t$

In this case, we have

$\begin{cases}0&\text{for }0\le t$

The Laplace transform of the step function is easy to compute:

$\displaystyle\int_0^\infty u(t-c)e^{-st}\,\mathrm dt=\int_c^\infty e^{-st}\,\mathrm dt=\frac{e^{-cs}}s$

So, taking the Laplace transform of both sides of the ODE, we get

$sY(s)-y(0)+5Y(s)=\dfrac{e^{-3s}-e^{-5s}}s$

Solve for $Y(s)$ :

$(s+5)Y(s)-4=\dfrac{e^{-3s}-e^{-5s}}s\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}{s(s+5)}+\dfrac4{s+5}$

We can split the first term into partial fractions:

$\dfrac1{s(s+5)}=\dfrac as+\dfrac b{s+5}\implies1=a(s+5)+bs$

If $s=0$ , then $1=5a\implies a=\frac15$ .

If $s=-5$ , then $1=-5b\implies b=-\frac15$ .

$\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}5\left(\frac1s-\frac1{s+5}\right)+\dfrac4{s+5}$

$\implies Y(s)=\dfrac15\left(\dfrac{e^{-3s}}s-\dfrac{e^{-3s}}{s+5}-\dfrac{e^{-5s}}s+\dfrac{e^{-5s}}{s+5}\right)+\dfrac4{s+5}$

Take the inverse transform of both sides, recalling that

$Y(s)=e^{-cs}F(s)\implies y(t)=u(t-c)f(t-c)$

where $F(s)$ is the Laplace transform of the function $f(t)$ . We have

$F(s)=\dfrac1s\implies f(t)=1$

$F(s)=\dfrac1{s+5}\implies f(t)=e^{-5t}$

We then end up with

$y(t)=\dfrac{u(t-3)(1-e^{-5t})-u(t-5)(1-e^{-5t})}5+5e^{-5t}$

3 0

3 years ago

Nvm <br>I don't need help

Snowcat [4.5K]

Answer:

ok

Step-by-step explanation:

5 0

1 year ago

Samantha is going to run in a 5K race. To prepare, she wants

user100 [1]

The number of minutes Samantha needs to run on Friday to reach her goal is 45 minutes.

<h3>Average</h3>

Monday = 45 minutes
Tuesday = 30 minutes
Wednesday = 55 minutes
Thursday = 25 minutes
Friday = x minutes

Average = (Monday + Tuesday + Wednesday + Thursday + Friday) / 5

40 = (45 + 30 + 55 + 25 + x) / 5

40 × 5 = 155 + x

200 = 155 + x

200 - 155 = x

45 = x

x = 45 minutes

Learn more about average:

brainly.com/question/20118982

#SPJ1

4 0

2 years ago

Which of the following possibilities will form a triangle?

Alenkinab [10]

I think the answer is A but I could be wrong

4 0

3 years ago

Read 2 more answers

What is 2 x 40/25 Two times forty over twenty-five