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DIA [1.3K]
3 years ago
9

Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation one-halfx2 + 4x + 8 = 0.

Which explanation could Anderson provide?
Mathematics
2 answers:
lidiya [134]3 years ago
4 0

Answer:

The equation has no real number solutions because the discriminant is less than 0.

Step-by-step explanation:

Its C on edg

amid [387]3 years ago
3 0

Answer:

The discriminant of ax^2+bx+c is b^2-4ac.  

If the discriminant, d, is:

d<0, there are no real solutions (there are two imaginary solutions however)

d=0, there is one real solution

d>0, there are two real solutions

In this case d=16-32=-16 so there are two imaginary solutions.  Or from your answer choices, it can be said that there are no real number solutions becuse the discriminant is less than zero.

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Write <br> 46.017<br> as a mixed number.
ddd [48]
17 is in the thousandths place, so we write it as a fraction over 1000.

17/1000

So we have:

46 17/1000
8 0
3 years ago
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Use the inequalities to describe the shaded area on the grid​
raketka [301]
The shaded area would be 2 because there is a whole square shaded in the the other two are 1/2 so if you add 1/2 together with another 1/2 plus the whole shaded square you would get two.


At least that’s what I understood from the question
8 0
3 years ago
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Consider a polynomial p(x) with a degree of 9. What is the largest possible number of x-intercepts and the largest possible numb
tia_tia [17]

Answer:

The largest possible number of x intercept is 9 while the largest possible number of relative max/min is 8

Step-by-step explanation:

For any polynomial of degree n with distinct and real solutions, it can have at most n different x intercepts. This would imply it can have at most 9 distinct real solutions.

It can also have at most n-1 relative max/min in alternating order. This is best illustrated when such polynomial is sketched on a graph.

For example a quadratic expression is a polynomial of degree 2 and has at most 2 distinct solutions and 1 relative max/min.

In this question, for the polynomial, its degree (n) = 9

So it can have at most 9 x intercepts and at most 8 relative max/min.

3 0
3 years ago
Can anyone help me with these i need them befire tomorrow
mash [69]
When you have a scale factor as percentage, is better to convert that percentage into a fraction by divide it by 100%. That way, it will be much easier to scale your figures.

1. 
The scale factor we need to apply to our rectangle is 60%. Firts, lets convert our scale factor into a fraction: \frac{60}{100} = \frac{3}{5}. Next, we just need to multiply each side of our rectangle by our fraction:
length=16( \frac{3}{5})=9.6
width=8( \frac{3}{5} )=4.8
So, our new rectangle will have a length of 9.6 units and a width of 4.8 units.

2. This time the scale factor is 120%. Just as before, lets convert it into a fraction: \frac{120}{100} = \frac{6}{5}, and just as before lets multiply each side of our triangle by our fraction:
base=10( \frac{6}{5} )=12
side=8( \frac{6}{5} )=9.6
So, our new isosceles triangle will have a base of 12 units and tow sides of length 9.6 units each.

3. This time the scale factor is 150%. Just as before, lets convert it into a fraction: \frac{150}{100} = \frac{3}{2}, and just as before lets multiply each side of our polygon by our fraction:
12( \frac{3}{2} )=18
15( \frac{3}{2} )=22.5
13( \frac{3}{2} )=19.5
So, our new polygon will have a side of 12 length units, tow sides of 15 length units, and two side of 15 length units.

4. This time our factor is 75%. Just as before, lets convert it into a fraction: \frac{75}{100} = \frac{3}{4}, and just as before lets multiply each side of our parallelogram by our fraction:
side=25( \frac{3}{4} )=18.75
So, our new parallelogram will have tow sides of length 18.75 units.

7 0
3 years ago
Which of the diagrams below represents the contrapositive of the statement
VMariaS [17]

Answer:

The correct figure is B.

Step-by-step explanation:

The statement provided is:

"If it is an equilateral triangle, then it is an isosceles triangle"

The contra-positive of a statement is determined by switching the hypothesis and conclusion of the provided statement and negating both.

Then the contra-positive of the statement provided will be:

  • Switching the hypothesis and conclusion:

        If it is an isosceles triangle - It is an equilateral triangle.

  • Negating both the statements:

        If it is not an isosceles triangle - it is not an equilateral triangle.

Thus, the contra-positive of the statement is:

"If it is not an isosceles triangle, then it is not an equilateral triangle."

Thus, the correct figure is B.

7 0
3 years ago
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