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loris [4]
3 years ago
12

Mr. Hamilton decorates his U.S. History classroom by putting up pictures of the presidents. The wall is 9.75 feet long. In the c

enter, there is a window that is 5 ¾ ​ feet long.
Each president's picture is 6 inches wide.

4. How would your answer change if the pictures were 10 inches wide? Explain.
Mathematics
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

The number of pictures changes from 8 to 4.

Step-by-step explanation:

I assume the first question was the number of pictures that could be placed when the pictures are 6 inches wide.

Let's first answer the first question.

Wall length: 9.75 ft

Window: 5¾ ft = 5.75 ft

Available wall space for pictures:

9.75 ft - 5.75 ft = 4 ft

Now we convert 4 ft to inches.

1 ft = 12 inches

4 ft = 4 * 12 inches = 48 inches

There is 48 inches of wall space to place pictures that measure 6 inches each.

48 inches / 6 inches = 8

Originally, there is room for 8 pictures.

Question 4.

Each picture is 10 inches wide.

There is still 48 inches of wall space for the pictures.

48 inches / 10 inches = 4.8

There is room for 4.8 pictures. Since Mr. Hamilton will place only whole picture, he can only place 4 pictures now.

Answer: The number of pictures changes from 8 to 4.

Nataliya [291]3 years ago
4 0

Answer:

8

Step-by-step explanation:

Given

Required

Determine the number of pictures

First, we need to calculate the length of the available space

This is calculated by subtracting the width of the window from the width of the wall.

Convert fraction to decimal

Since, the pictures are placed side by side.

This means that, there's no empty space between them.

Number of pictures is:

Convert feet to inches

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Jack lives east of NJH and finn lives west of NJH. Jack leaves right after school and rides his bike home at an average speed of
Vlada [557]

Answer:

Distance between NJH and Jack's home  = 7.10 miles

Distance between NJH and Finn's home  = (14-7.10) = 6.9 miles

Step-by-step explanation:

Given:

Jack lives east of NJH and Finn lives west of NJH.

Distance between Jack and Finn's home = 14 miles

Average speed of Jack = 7 mph

Average speed of Finn = 9 mph

Let the distance between Jack's house and NJH is '(x)' miles.

So the distance between Finn's house and NJH is '(14-x)' miles.

According to the question:

Time taken by both Finn and Jack are equal to reach home.

Considering t_1 is the time taken by Jack and t_2 is the time taken by Finn to reach home.

So,

⇒ t_1=t_2

We have to find the time taken.

⇒ Time taken by Jack.            ⇒ Time taken by Finn.

⇒ t_1=\frac{distance}{speed}                          ⇒ t_2=\frac{distance}{speed}

⇒ t_1=\frac{x}{7} mph                           ⇒ t_2=(\frac{14-x}{9} + \frac{15\ min}{60\ min}) mph   <em> ...15 min extra </em>

  Equating both t_1 and t_2 :

⇒ t_1=t_2

⇒ \frac{x}{7} =\frac{14-x}{9} +\frac{1}{4}

⇒ \frac{x}{7} =\frac{56-4x+9}{36}

⇒ \frac{x}{7} =\frac{65-4x}{36}

⇒ Cross multiplying.

⇒ x(36)=7(65-4x)

⇒ 36x=455-28x

⇒ 36x+28x=455

⇒ 64x=455

⇒ x=\frac{455}{64}

⇒ x=7.10 miles

Distance between NJH and Jack's home = (x) = 7.10 miles

Distance between NJH and Finn's home = (14-x) = (14-7.10) = 6.9 miles

6 0
3 years ago
A machine fills boxes with cereal. The boxes are labeled as containing 24 ounces but there is some variability; the amount depos
m_a_m_a [10]

Answer:

The mean amount of cereal in a box must be 23.42 ounces.

Step-by-step explanation:

Let <em>X</em> = amount of cereal in a box.

It is provided that <em>X</em> follows a normal distribution with mean <em>μ</em> and standard deviation <em>σ</em> = 0.25.

If 99% of the boxes contain 24 ounces or more of cereals then the probability statement is:

\geq P(X \geq 24) = 0.99\\P(\frac{X-\mu}{\sigma}\geq  \frac{24-\mu}{0.25})=0.99\\P(Z \geq z)=0.99\\1-P(Z

Use the <em>z</em> table to determine the <em>z-</em>value.

The value of <em>z</em> is -2.33.

Determine the value of <em>μ</em> as follows:

\frac{24-\mu}{0.25}=-2.33 \\\mu=24-(2.33\times 0.25)\\=23.4175\\\approx23.42

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7 0
4 years ago
Help!! Number 39 please
antiseptic1488 [7]
Keep in mind you would need a total of 120 ounces.
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B: 12c+ 15w= 120 (c= corn cereal, w= wheat cereal)
C: 5 boxes of corn cereal with 4 boxes of wheat cereal; 0 boxes of corn cereal with 8 boxes of wheat cereal; 10 boxes of corn cereal with 0 boxes of wheat cereal.
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