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Blababa [14]
2 years ago
9

What would an equation be for 6 bags of flyers each bag containing 12 flyers

Mathematics
2 answers:
enyata [817]2 years ago
7 0

Answer:

6x12

Step-by-step explanation:

garri49 [273]2 years ago
6 0

Answer:

6 multiplied by 12

Step-by-step explanation:

you have 6 bags, each bag contains 12 flyers

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2. Calculate the angular speed of the 26-inch bicycle rotating at 200 revolutions per minute. Express your answer in radians per
Alexus [3.1K]
The angular velocity for this problem is given by:
 Angular speed = 200 rev / min
 The first thing you should keep in mind is the following conversion:
 1 rev = 2π radians
 Applying the conversion we have:
 Angular speed = 200 * (2π)
 Rewriting:
 Angular speed = 200 * (2 * 3.14)
 Angular speed = 1256 radians / minutes
 Answer:
 
the angular speed is:
 
Angular speed = 1256 radians / minutes
4 0
3 years ago
F(x) = x + 2 when x = 10
murzikaleks [220]

Answer:

f(10) = 12

Step-by-step explanation:

f(x) = x + 2

Substitute x for 10.

f(10) = 10 + 2

f(10) = 12

8 0
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Zina [86]

Answer:

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Step-by-step explanation:

3 0
3 years ago
A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a sin
Tatiana [17]

Answer: 1/52

Step-by-step explanation:

A deck of cards contains 52 cards

Red cards are numbered 1,2,3

Blue cards are numbered 1,2,3,4,5,6

Green cards are numbered 1,2

Number of Red card = 3

Number of blue card = 6

Number of Green card = 2

Let Pr(R) = Probability of picking a Red card

Let Pr(B) = probability of picking a blue card

Let Pr(G) = probability of picking a green card

Let Pr(RE) = Probability of picking a red even card

Let Pr(RO) = probability of picking a red odd card

Let Pr(BE) =probability of picking a blue even card

Let Pr(BO) = probability of picking a blue odd card

Let Pr(GE) = probability of picking a green even card

Let Pr(GO) = probability of picking a green odd card

Pr(R) = 3/52

Since we have 3 red cards,

Pr(RE) = 1/3

Pr(RO) =2/3

Pr(B) = 6/52

= 3/26

Since we have 6 blue cards ,

Pr(BE) = 3/6

= 1/2

Pr(BO) = 3/6

= 1/2

Pr (G) = 2/52

= 1/26

Since we have 2 green cards,

Pr(GE) = 1/2

Pr(GO) = 1/2

The probability of picking a Green card and an odd green card is

Pr(G) n pr(GO)

1/26 * 1/2

= 1/52

5 0
3 years ago
Point P is the midpoint of DE.
Leto [7]

Answer:A.4

Step-by-step explanation:

6 0
3 years ago
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