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Contact [7]
3 years ago
15

Ma poate ajuta cineva la acesta problema: pe o drepta g considerati punctele D, R,P si T coliniare in aceasta ordine astfel inca

t DR=PT=3 cm, iar RP=4cm

Mathematics
1 answer:
valina [46]3 years ago
8 0

Answer:

Givens

DR=PT=3cm and RP=4cm

Points D, R, P and T are collinear.

The image attached shows a representation of this problem.

By sum of segments, we have

DT=DR+RP+PT

Replacing all given values, we have

DT=3+4+3=10 \ cm

Therefore, the segment DT is 10 centimeters long.

Now, we know that point E is the center of segment RP, which means is a middle point, divides the segment equally. So, to prove that segment DT is symmetrical regarding point E, we need to prove that both sides are equal.

RE=EP=2cm, by definition of middle point.

By sum of segments, we have

DR+RE=3+2=5cm\\EP+PT=5cm

Which means DR+RE=\frac{DT}{2}\\ EP+PT=\frac{DT}{2}.

Therefore, segment DT is symmetrical regarding point E.

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