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Lana71 [14]
3 years ago
15

If 3a + b + c = -3, a+3b+c = 9, a+b+3c = 19 find a*b*c

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

a=-4

b=2

c=7

so therefore a*b*c=-4*2*7

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Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

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The general solution for first a first order DE is expressed as;

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yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
7. Which correctly describes the graph shown
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Answer:

A) linear; function

Step-by-step explanation:

hope this helps and hope you have a good day and please mark me brainliest

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2 years ago
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3 0
3 years ago
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Written in simplest form explain how you found the answer
Anettt [7]
The answer is dividing stuff
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3 years ago
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