If 3a + b + c = -3, a+3b+c = 9, a+b+3c = 19 find a*b*c
1 answer:
You might be interested in
Let the first and smaller number be x. Since the second number is 5 times the first, the second number is 5x. We also know both of these numbers must add to 50; thus, we can create the following equation.
Combine like terms
Divide both sides by 6
This is the value of the first number. The number you're looking for isn't specified in the question description, so I'll just provide the value of the second number. The second number has to be 5 times the first.
Thus, we just multiply 5 to x.
That's the value of the second number.