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PIT_PIT [208]
3 years ago
6

It is possible a tree could fall down, even if no one did anything to it. A. True B. False

Physics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

This is TRUE

Explanation:

The tree can fall down even though no one did anything to it...

A hard breeze can blow and it can fall down or something else can cause it to topple...

Not only humans can make trees topple over...

<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>

<em>Bonne journée</em><em> </em><em>;</em><em>)</em><em> </em>

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The 100 meter dash is a quick and short run requiring explosive speed. on completion of the dash the runners will continue to br
Alisiya [41]
<span>Because you are running so fast, your body produces a lot of lactate. Along with this lactate comes a hydrogen ion (H+), and you can’t have too many of these in the body because they will make the body fluids acidic. So the body “buffers” the H+ using biocarbonate (HCO3-) which produces CO2 and H2O. This raises the CO2 concentration of your blood, which is detected by receptors in the aorta and carotid arteries, and the respiratory centre of the brain, which then causes you to breath more deeply and more frequently.</span>
7 0
3 years ago
A car with mass mc = 1490 kg is traveling west through an intersection at a magnitude of velocity of vc = 9.5 m/s when a truck o
icang [17]

Answer:

v= - 4.507 i - 2.363 j

Explanation:

 Given that

mc= 1490 kg

vc= 9.5 m/s ( - i)

mt=  1650 kg

vt = 6.4 m/s ( -j)

There is any external force so linear momentum will remain conserve.

Lets take final speed is v.

mc .vc + mt . vt = ( mc+mt) v

1490 x 9.5 ( - i) + 1650 x 6.4 ( -j) = ( 1490+1650) v

14,155 ( -i) + 10,560 ( - j) = 3140 v

v= - 4.507 i - 2.363 j

3 0
4 years ago
What is the frequency of highly energetic ul-
Mnenie [13.5K]

Frequency = (speed) / (wavelength)

Frequency = (3 x 10⁸ m/s) / (124 x 10⁻⁹ m)

Frequency = <em>2.42 x 10¹⁵ Hz</em>

8 0
3 years ago
10) The closest star to the earth (other than
Reptile [31]

Answer:

It takes a little, be patient.

8 0
4 years ago
Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.
Lelechka [254]

Answer:

Option A (69.56 newtons) is the appropriate solution.

Explanation:

According to the question,

On the X-axis,

⇒ T_1Cos30^{\circ}-T_2Cos60^{\circ}=0

or,

    T_1Cos 30^{\circ}=T_2Cos60^{\circ}

On substituting the values, we get

      T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}

      T_1\times \sqrt{3} =T_2....(equation 1)

On the Y-axis,

⇒ T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N

                        \frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N

                    T_1+\sqrt{3}T_2=139.2\times 2

From equation 1, we get

           T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N

                        T_1+3T_1=278.4 \ N

                                4T_1=278.4 \ N

                                  T_1=\frac{278.4}{4}

                                       =69.6 \ N  

6 0
3 years ago
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